问题描述
我在下面的查询中使用 week_number type ， amount 和 total /code>列.
I have below query which gives me data with three columns - type, amount and total for previous week using week_number column.
select type,
case
WHEN (type = 'PROC1' AND contractdomicilecode = 'UIT') THEN 450
WHEN (type = 'PROC1' AND contractdomicilecode = 'KJH') THEN 900
WHEN (type = 'PROC2' AND contractdomicilecode = 'LOP') THEN 8840
WHEN (type = 'PROC2' AND contractdomicilecode = 'AWE') THEN 1490
WHEN (type = 'PROC3' AND contractdomicilecode = 'MNH') THEN 1600
WHEN (type = 'PROC3' AND contractdomicilecode = 'LKP') THEN 1900
END as amount,
total
from xyz.orders pa
join
(select clientid as clientid, max(version) as version
from xyz.orders where consumerid IN (select distinct entity_id from abc.items
where week_number = extract(week from current_date) - 1
and item_type like '%Ionize - Data%' )
and createdfor ='BLOCK'
and holder='RELAY_FUTURES'
group by clientid) pb on
pa.clientid = pb.clientid and pa.version = pb.version;
下面是我上面查询得到的结果:
Below is the output I get back as of now with above query:
type amount total
---------------------------
PROC1 450 1768
PROC1 900 123
PROC1 450 456
PROC2 8840 99897
PROC2 1490 2223
PROC2 8840 9876
PROC3 1900 23456
PROC3 1600 12498
PROC3 1600 28756
问题陈述
现在，我试图找出一种方式来获取过去6周(不包括当前周)的数据.基本上，我希望在过去6周内获得每种类型的 amount ， total ，如下所示.
Now I am trying to figure out a way by which I can get data for past 6 weeks (not including current week). Basically I want to get amount, total for each type for past 6 weeks as shown below.
week type amount total
----------------------------------
46 PROC1 450 1768
46 PROC1 900 123
46 PROC1 450 456
46 PROC2 8840 99897
46 PROC2 1490 2223
46 PROC2 8840 9876
46 PROC3 1900 23456
46 PROC3 1600 12498
46 PROC3 1600 28756
45 PROC1 450 1768
45 PROC1 900 123
45 PROC1 450 456
45 PROC2 8840 99897
45 PROC2 1490 2223
45 PROC2 8840 9876
45 PROC3 1900 23456
45 PROC3 1600 12498
45 PROC3 1600 28756
44 PROC1 450 1768
44 PROC1 900 123
44 PROC1 450 456
44 PROC2 8840 99897
44 PROC2 1490 2223
44 PROC2 8840 9876
44 PROC3 1900 23456
44 PROC3 1600 12498
44 PROC3 1600 28756
43 PROC1 450 1768
43 PROC1 900 123
43 PROC1 450 456
43 PROC2 8840 99897
43 PROC2 1490 2223
43 PROC2 8840 9876
43 PROC3 1900 23456
43 PROC3 1600 12498
43 PROC3 1600 28756
42 PROC1 450 1768
42 PROC1 900 123
42 PROC1 450 456
42 PROC2 8840 99897
42 PROC2 1490 2223
42 PROC2 8840 9876
42 PROC3 1900 23456
42 PROC3 1600 12498
42 PROC3 1600 28756
41 PROC1 450 1768
41 PROC1 900 123
41 PROC1 450 456
41 PROC2 8840 99897
41 PROC2 1490 2223
41 PROC2 8840 9876
41 PROC3 1900 23456
41 PROC3 1600 12498
41 PROC3 1600 28756
这有可能吗?
推荐答案
如果第列是第1行的第一个: select 之后，则可以尝试将以下代码添加到查询中 xyz.orders 表中存在current_date
You may try adding the following code to your query, right after the first select in line 1, if the column current_date is present in the xyz.orders table:
extract(week from current_date) as week,
要获取过去的星期数(在您的情况下为6周)，将在xyz.orders pa 中的行之后使用过滤器:
To obtain the past number of weeks (6 in your case), a filter will be used after the line of from xyz.orders pa:
where datediff(week, extract(week, current_date)-6, extract(week, current_date)+1) = 6
过滤器可能需要稍作调整，但是当您看到输出时，您应该能够找到需要调整的内容.
The filter might need to be slightly adjusted, but when you see the output you should be able to find what needs to be adjusted.
MS文档的上述过滤器中使用的 DATEDIFF 函数中的更多信息可能是有用的参考.
Some more info in the DATEDIFF function used in the filter above from the MS docs might be a helpful reference.
在进行了上述更改之后，以下是有关从原始代码添加的详细信息的更新的查询和注释.
With the above changes, here is the updated query and comments as to the specifics added from your original code.
select
extract(week from current_date) as week, -- added code
type,
case
WHEN (type = 'PROC1' AND contractdomicilecode = 'UIT') THEN 450
WHEN (type = 'PROC1' AND contractdomicilecode = 'KJH') THEN 900
WHEN (type = 'PROC2' AND contractdomicilecode = 'LOP') THEN 8840
WHEN (type = 'PROC2' AND contractdomicilecode = 'AWE') THEN 1490
WHEN (type = 'PROC3' AND contractdomicilecode = 'MNH') THEN 1600
WHEN (type = 'PROC3' AND contractdomicilecode = 'LKP') THEN 1900
END as amount,
total
from xyz.orders pa
where datediff(week, extract(week, current_date)-6, extract(week, current_date)+1) = 6 -- added code
join
(select clientid as clientid, max(version) as version
from xyz.orders where consumerid IN (select distinct entity_id from abc.items
where week_number = extract(week from current_date) - 1
and item_type like '%Ionize - Data%' )
and createdfor ='BLOCK'
and holder='RELAY_FUTURES'
group by clientid) pb on
pa.clientid = pb.clientid and pa.version = pb.version;
这篇关于如何获取过去x周每种类型的数据?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！