本文介绍了Neo4j GraphRepository派生的查找器方法的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我对GraphRepository的派发查找器方法有疑问.

I have a problem with derived finder methods of GraphRepository.

简短版本:

User foundUser1 = userRepository.findByEmail("[email protected]");
User foundUser2 = userRepository.findByPropertyValue("id", 1);

有效,但无效:

User foundUser3 = userRepository.findById(1);

长版:

test-context.xml

<context:annotation-config/>    
<neo4j:config storeDirectory="data/graph.db" />
<neo4j:repositories base-package="com.blbl.repository"/>
<tx:annotation-driven mode="proxy"/>

UserGraphRepository.java:

public interface UserGraphRepository extends GraphRepository<User> {
    public User findById(int id);
    public User findByEmail(String email);    
}

User.java:

@NodeEntity
public class User {
    @GraphId private Long nodeId;
    @Indexed(unique = true) private int id;
    @Indexed private String email;

    public User(int id) {
        this.id = id;
    }
    // getter & setters
}

测试:

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration({"/test-context.xml"})
@Transactional
public class UserServiceTest {

    @Autowired
    private UserGraphRepository userRepository;

    @Autowired
    private Neo4jTemplate template;


    @BeforeTransaction
    @Rollback(value = false)
    public void cleanDb() {
        Neo4jHelper.cleanDb(template);
    }

    @Test
    public void testSaveUser() {
        User user = userRepository.save(new User(1));
        user.setEmail("[email protected]");
        userRepository.save(user);

        User foundUser1 = userRepository.findByEmail("[email protected]");
        User foundUser2 = userRepository.findByPropertyValue("id", 1);
        User foundUser3 = userRepository.findById(1);
        assertThat(foundUser1, is(notNullValue())); // SUCCESS
        assertThat(foundUser2, is(notNullValue())); // SUCCESS
        assertThat(foundUser3, is(notNullValue())); // FAILS
    }
}

第三个断言失败,因为foundUser3为null.我不明白为什么会发生这种情况,尽管它可以通过findByPropertyValue("id" ..)找到.我想知道 id 是否是某种关键字吗? (请注意,我的@GraphId被称为nodeId)

third assert fails since foundUser3 is null. I don't understand why this is happening while it can find with findByPropertyValue("id" ..). I wonder if id is some sort of keyword? (Note that my @GraphId is called nodeId)

PS:

<neo4j-version>1.8.M07</neo4j-version>
<org.springframework.version>3.1.2.RELEASE</org.springframework.version>
<org.springframework-data-neo4j.version>2.1.0.RC3</org.springframework-data-neo4j.version>

推荐答案

这可能是对数字字段进行特殊索引的问题.我在这里提出了一个问题: https://jira.springsource.org/browse/DATAGRAPH-294

This is probably an issue with special indexing of numeric fields. I raised an issue here: https://jira.springsource.org/browse/DATAGRAPH-294

这篇关于Neo4j GraphRepository派生的查找器方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-17 05:26