如何拒绝/关闭特定的来电号码

问题描述

在我的应用程序，我想阻止特定的传入number.I做谷歌，并遵循的。但是，这code是不工作的我，我正在测试的安卓2.3.5

在这里，我没有任何活动类。 >>第一类是扩展的BroadcastReceiver。

的manifest.xml

 ＆LT; XML版本=1.0编码=UTF-8＆GT？;
＆LT;舱单的xmlns：机器人=htt​​p://schemas.android.com/apk/res/android
包=com.blocknumber
安卓版code =1
机器人：VERSIONNAME =1.0＆GT;

＆LT;用途-SDK
    安卓的minSdkVersion =8
    机器人：targetSdkVersion =17/＆GT;

＆LT;使用-权限的Andr​​oid：名称=android.permission.READ_PHONE_STATE/＆GT;
＆LT;使用-权限的Andr​​oid：名称=android.permission.CALL_PHONE/＆GT;
＆LT;使用-权限的Andr​​oid：名称=android.permission.MODIFY_PHONE_STATE/＆GT;
＆LT;使用-权限的Andr​​oid：名称=android.permission.PROCESS_INCOMING_CALLS/＆GT;

＆lt;应用
    机器人：allowBackup =真
    机器人：图标=@可绘制/ ic_launcher
    机器人：标签=@字符串/ APP_NAME
    机器人：主题=@风格/ AppTheme＆GT;
    ＆LT;接收机器人：名称=。MainActivity＆GT;
        ＆LT;意向滤光器＆gt;
            ＆lt;作用机器人：名称=android.intent.action.PHONE_STATE/＆GT;
        ＆所述; /意图滤光器＆gt;
    ＆LT; /接收器＆GT;
＆LT; /用途＆gt;
 

MainActivity.class

 公共类MainActivity扩展的BroadcastReceiver {

公共无效的onReceive（上下文的背景下，意图意图）{
    串blockedNumbers [] = {XXXXXXXXXX，XXXXXXXXXX};
    叠B = intent.getExtras（）;
    / *
     *字符串incommingNumber = B
     * .getString（TelephonyManager.EXTRA_INCOMING_NUMBER）;
     * /
    串incommingNumber = b.getString（incoming_number）;
    Log.e（进来的数量========＆gt;中，incommingNumber）;
    //字符串状态= intent.getStringExtra（TelephonyManager.EXTRA_STATE）;

    的for（int i = 0; I＆LT; blockedNumbers.length;我++）{
        Log.e（进来的＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT;＆GT; ======＆gt;中，+ I）;
        如果（incommingNumber.equalsIgnoreCase（blockedNumbers [I]））{
            TelephonyManager电话=（TelephonyManager）上下文
                    .getSystemService（Context.TELEPHONY_SERVICE）;
            尝试 {
                类＆LT;＆GT; C =的Class.forName（telephony.getClass（）的getName（））;
                方法米= c.getDeclaredMethod（getITelephony）;
                m.setAccessible（真正的）;
                ITelephony telephonyService =（ITelephony）M
                        .invoke（电话）;
                // telephonyService.silenceRinger（）;
                telephonyService.endCall（）;
            }赶上（例外五）{
                e.printStackTrace（）;
            }
        }
    }

}
}
 

ITelephony

 公共接口ITelephony {

    布尔结束呼叫（）;

    无效answerRingingCall（）;

    //无效silenceRinger（）;

}
 

解决方案

最后，解决问题，创建IDL接口获取核心电话服务包的名称必须是 com.android.internal.telephony

文件名： ITelephony.aidl //首先在这里我createing ITelephony.java

对于创建的 .aidl 文件最新及GT;文件写 ITelephony.aidl

和遵循的步骤<一href="http://androiddesk.word$p$pss.com/2012/08/02/blocking-a-call-without-user-intervention-in-android/#comments"相对=nofollow>禁止在Android的呼叫，而无需用户干预的例子。

In my application I want to block the specific incoming number.I do google,and following Blocking Incoming call - Android. But this code is not working for me.I am testing on android 2.3.5

Here I have no activity class. >> First class is extends BroadcastReceiver.

manifest.xml

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.blocknumber"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk
    android:minSdkVersion="8"
    android:targetSdkVersion="17" />

<uses-permission android:name="android.permission.READ_PHONE_STATE" />
<uses-permission android:name="android.permission.CALL_PHONE" />  
<uses-permission android:name="android.permission.MODIFY_PHONE_STATE" /> 
<uses-permission android:name="android.permission.PROCESS_INCOMING_CALLS" />

<application
    android:allowBackup="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme" >
    <receiver android:name=".MainActivity" >
        <intent-filter>
            <action android:name="android.intent.action.PHONE_STATE" />
        </intent-filter>
    </receiver>
</application>

MainActivity.class

public class MainActivity extends BroadcastReceiver {

public void onReceive(Context context, Intent intent) {
    String blockedNumbers[] = { "xxxxxxxxxx", "xxxxxxxxxx" };
    Bundle b = intent.getExtras();
    /*
     * String incommingNumber = b
     * .getString(TelephonyManager.EXTRA_INCOMING_NUMBER);
     */
    String incommingNumber = b.getString("incoming_number");
    Log.e("Incomming number========>", incommingNumber);
    // String state = intent.getStringExtra(TelephonyManager.EXTRA_STATE);

    for (int i = 0; i < blockedNumbers.length; i++) {
        Log.e("Incomming >>>>>>>>>>>>>========>", "" + i);
        if (incommingNumber.equalsIgnoreCase(blockedNumbers[i])) {
            TelephonyManager telephony = (TelephonyManager) context
                    .getSystemService(Context.TELEPHONY_SERVICE);
            try {
                Class<?> c = Class.forName(telephony.getClass().getName());
                Method m = c.getDeclaredMethod("getITelephony");
                m.setAccessible(true);
                ITelephony telephonyService = (ITelephony) m
                        .invoke(telephony);
                // telephonyService.silenceRinger();
                telephonyService.endCall();
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }

}
}

ITelephony

public interface ITelephony {

    boolean endCall();

    void answerRingingCall();

    //void silenceRinger();

}

解决方案

Finally, solve the issue,Create IDL interface for getting core Telephony servicepackage name must be com.android.internal.telephony

FileName : ITelephony.aidl // First Here I am createing ITelephony.java

For the create .aidl file New > File and write ITelephony.aidl

And follow the steps Blocking a call without user intervention in android with an example.

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