服务的任何公共方法的 AOP 切入点表达式

问题描述

拦截所有用@Service 注释的bean 的所有公共方法的最简单的切入点表达式是什么?例如，我希望它影响这个 bean 的两个公共方法:

What is the simplest pointcut expression that would intercept all public methods of all beans annotated with @Service? For instance, I expect it to affect both public methods of this bean:

@Service
public MyServiceImpl implements MyService {
    public String doThis() {...}
    public int doThat() {...}
    protected int doThatHelper() {...} // not wrapped
}

推荐答案

这个 文档 应该非常有用.

This documentation should be extremely helpful.

我会创建两个单独的切入点，一个用于所有公共方法，一个用于所有用@Service 注释的类，然后创建第三个结合其他两个切入点表达式的切入点.

I would do by creating two individual point cuts, one for all public methods, and one for all classes annotated with @Service, and then create a third one that combines the pointcut expressions of the other two.

查看(7.2.3.1 支持的切入点指示符)要使用的指示符.我认为您在寻找公共方法的执行"指示符和用于查找注释的注释"指示符.

Take a look at (7.2.3.1 Supported Pointcut Designators) for which designators to use. I think you are after 'execution' designator for finding public methods, and the 'annotation' designator for finding your annotation.

然后看一下(7.2.3.2 组合切入点表达式)来组合它们.

Then take a look at (7.2.3.2 Combining pointcut expressions) for combining them.

我在下面提供了一些代码(我没有测试过).它主要取自文档.

I have provided some code below (which I have not tested). It is mostly taken from the documentation.

@Pointcut("execution(public * *(..))") //this should work for the public pointcut
private void anyPublicOperation() {}

//@Pointcut("@annotation(Service)") this might still work, but try 'within' instead
@Pointcut("@within(Service)") //this should work for the annotation service pointcut
private void inTrading() {}

@Pointcut("anyPublicOperation() && inTrading()")
private void tradingOperation() {}

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