仅用于特定参数的 Rspec 存根方法

问题描述

有没有办法只为特定参数存根方法.像这样

Is there a way to stub method for only specific arguments. Something like this

boss.stub(:fire!).with(employee1).and_return(true)

如果任何其他员工被传递给 boss.fire! 方法，我会得到 boss received unexpected message 错误，但我真正想要的只是覆盖具体论证的方法，留给所有其他人.

If any other employee is passed to boss.fire! method, I'll get boss received unexpected message error, but what I would really like is just to override the method for specific argument, and leave it be for all others.

知道如何做到这一点吗?

Any ideas how this can be done?

推荐答案

您可以为将调用原始实现的 fire! 方法添加默认存根:

You can add a default stub for the fire! method which will call original implementation:

boss.stub(:fire!).and_call_original
boss.stub(:fire!).with(employee1).and_return(true)

Rspec 3 语法 (@pk-nb)

Rspec 3 Syntax (@pk-nb)

allow(boss).to receive(:fire!).and_call_original
allow(boss).to receive(:fire!).with(employee1).and_return(true)

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