问题描述
我敢肯定有一个简单的答案,但是我已经扫描了堆栈溢出并且没有找到解决方案.似乎将sapply和ifelse函数结合起来可以完成这项工作(但我不确定).
I'm sure there is an easy answer for this , but I have scanned stack overflow and haven't been able to find a solution. It would seem that potentially a combination of sapply and ifelse functions would do the job (but I'm not sure).
所以我有一个带有字符的数据框,除了一列是数字值之外.
So I have a dataframe with characters, except one column which is a numeric value.
####Create dataframe which needs converting
df <- data.frame(Sample_1 = rep(letters[1:3], each = 3),
Sample_2 = rep("a", times = 9))
df$Number <- rep(seq(from=1,to=3,by=1))
我想将此数据框中的字符转换为特定数字.字符需要转换为何种字符取决于最后一列中的数字.因此标准是:
I would like to convert the characters in this dataframe to a specific number. What the character needs to be converted to depends on the number in the final column. So the criteria would be:
- 如果Number = 1,则a应更改为30,b应更改为20,c应更改为10
- 如果Number = 2,则a应该更改为35,b应该更改为25,c应该更改为15
- 如果Number = 3,则a应该更改为40,b应该更改为30,c应该更改为20
以下是突出显示此转化的数据框
Here is a dataframe highlighting this conversion
A <- c(30,20,10)
B <- c(35,25,15)
C <- c(40,30,20)
Conversion_df <- data.frame(A, B,C)
这是所需的输出.
Final <- data.frame(Sample_1 = c(30,20,10,35,25,15,40,30,20),
Sample_2 = c(30,20,10,30,20,10,30,20,10))
在此先感谢您的帮助.
Thank you in advance for any help.
推荐答案
首先,我们可以使用if语句创建一个函数来评估样本:
First we can create a function to valuate the sample with if's statements:
valuate_sample <- function(x,y) {
ifelse(y==1, ifelse(x=='a',30, ifelse(x=='b',20, 10)),
ifelse(y==2, ifelse(x=='a',35, ifelse(x=='b',25, 15)),
ifelse(y==3, ifelse(x=='a',40, ifelse(x=='b',30, 20)),0)))
}
在我们只需要在您的数据框中使用该函数之后:
After we just need to use the function in your dataframe:
df <- df %>%
mutate(
Sample_1 = valuate_sample(Sample_1, Number),
Sample_2 = valuate_sample(Sample_2, Number)
)
结果:
这篇关于有条件地将字符串转换为特定的数值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!