我如何打破无限的while循环与用户输入

问题描述

我是Python的新手.

I'm very new to Python.

我制作了一个数学程序，每次您获得最后一个正确答案时，都会不断产生新的数学问题.但是我不知道如何退出/中断while True循环并从加法转换为减法.

I made a math program that keeps generating a new math problem every time you get the last one right. however I don't know how to exit/break the while True loop and switch from addition to subtraction.

import random

while True:

    question = input("press 1 for addition, press 2 for subtraction.")
    if question == "1":
        print("Try your skill at these problems.")
        number1 = random.randint(0, 9)
        number2 = random.randint(0, 9)

        while True:
            print(number1, "+", number2, "=")
            number3 = number1+number2
            answer = int(input())
            if answer == number3:
                print("Great Job, Try this one.")
                number1 = random.randint(0, 9)
                number2 = random.randint(0, 9)
            else:
                print("Have another go")
            #I want to push space to break this while loop
            #and be able to switch to subtraction problems
    if question == "2":
        print("Try your skill at these problems.")
        number1 = random.randint(0, 9)
        number2 = random.randint(0, 9)

        while True:
            print(number1, "-", number2, "=")
            number3 = number1-number2
            answer = int(input())
            if answer == number3:
                print("Great Job, Try this one.")
                number1 = random.randint(0, 9)
                number2 = random.randint(0, 9)
            else:
                print("Have another go")
            #I want to push space to break this while loop
            #and be able to switch to addition problems

如何指定用户输入(例如空格键)来制动while True:循环.我看过发布给类似问题的其他答案，但是当我尝试它们时，它们都阻止了我的代码生成大量问题.

how do I specify a user input (e.g. space bar) to brake the while True: loop. I've looked at other answers posted to similar questions but when I try them they all stop my code from generating more than a set number of problems.

有没有办法做到这一点.还是我需要找到一种在没有True循环的情况下运行此数学游戏的方法?

Is there a way to do this. or do I need to find a way to run this math game without a while True loop?

推荐答案

当无法确定循环次数时，最好使用while循环，对于使用while循环的方法来说做得很好.

It is good to use while loop when the number of looping cannot be determined, Well done for your approach using while loop.

如果要退出while循环，可以尝试在while循环之外定义一个变量(条件变量)，并将该变量设置为while条件.要退出循环，只需更改条件变量的值即可.

If you want to exit the while loop, you can try to define a variable(conditions variable) outside the while loop, and set the variable become your while conditions. And to exit the loop, just change the value of the conditions variable.

代码示例:

import random

while True:

    conditions = True # my changes
    question = input("press 1 for addition, press 2 for subtraction.")
    if question == "1":
        print("Try your skill at these problems.")
        number1 = random.randint(0, 9)
        number2 = random.randint(0, 9)

        while conditions: # my changes
            print(number1, "+", number2, "=")
            number3 = number1+number2
            answer = int(input())
            if answer == number3:
                print("Great Job, Try this one.")
                number1 = random.randint(0, 9)
                number2 = random.randint(0, 9)
                checking = input("Another round? (Y/N)") # my changes
                if checking == "N": # my changes
                    conditions = False # my changes
            else:
                print("Have another go")
    if question == "2":
        print("Try your skill at these problems.")
        number1 = random.randint(0, 9)
        number2 = random.randint(0, 9)

        while conditions: # my changes
            print(number1, "-", number2, "=")
            number3 = number1-number2
            answer = int(input())
            if answer == number3:
                print("Great Job, Try this one.")
                number1 = random.randint(0, 9)
                number2 = random.randint(0, 9)
                checking = input("Another round? (Y/N)") # my changes
                if checking == "N": # my changes
                    conditions = False # my changes
            else:
                print("Have another go")

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