问题描述
我有一个静态库,liborc-0.4.a没有共享库。我有依赖于liborc-0.4.a符号另一个库,libschroedinger-1.0.a(不共享)。如果我运行liborc-0.4.a纳米,如orc_init符号显示为T(意思是它们被定义)。我建libschroedinger-1.0.a与-lorc-0.4,因此看到的符号和是确定的命令行标志。
I have a static library, liborc-0.4.a with no shared library. I have another library, libschroedinger-1.0.a (no shared) that depends on symbols in liborc-0.4.a. If I run nm on liborc-0.4.a, symbols such as orc_init show up as T (meaning they are defined). I built libschroedinger-1.0.a with the command line flag -lorc-0.4 so it saw the symbols and was ok.
不过,现在我有一个小的可执行文件,它取决于libschroedinger-1.0.a。它编译罚款,但是当我运行链接 GCC -lschroedinger-1.0 -lorc-0.4输出-o input.o
它给出了错误,例如:
However, now I have a small executable that depends on libschroedinger-1.0.a. It compiles fine, but when I run the linker gcc -lschroedinger-1.0 -lorc-0.4 -o output input.o
It gives errors such as:
/usr/local/lib/libschroedinger-1.0.a(libschroedinger_1.0_la-schro.o):schro.c :(文字+ 0×21):未定义的参考`orc_init
我该如何解决这个问题?感谢名单。
How can I fix this? Thanx.
推荐答案
GCC
是库的顺序敏感。当它编译 liborc-0.4.a
中,没有必要为 orc_init
,所以它不包括在内。解决的办法是把 LDFLAGS
在命令的末尾:
gcc
is sensitive to the order of libraries. When it's compiling liborc-0.4.a
in, there is no need for orc_init
, so it's not included. The solution is to put the LDFLAGS
at the end of the command:
gcc -o output input.o -lschroedinger-1.0 -lorc-0.4
这篇关于静态库符号不被使用-l竟然发现的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!