math.floor 应该返回整数

问题描述

我想在两个变量相除后得到一个数的整数部分.即，如果值为 3.75，则为 3displaycount 和 itemcount 都是整数变量.

I am trying to get the integer part of a number after dividing two variables.ie, get 3 if the value is 3.75displaycount and itemcount are both integer variables.

    Dim cntr As Integer        
    cntr = Math.Floor(Math.Abs(itemCount / displaycount))

该代码在 VS2012 中产生蓝色波浪线，注释为将 Double 转换为整数时可能会出现运行时错误"，但 Math.Floor 应该采用小数或双精度并返回整数.

That code produces a blue squiggly in VS2012 with the comment that "runtime errors may occur when converting Double to Integer" BUT Math.Floor is supposed to take a decimal or double and return an integer.

推荐答案

Math.Floor 应该采用小数或双精度并返回一个整数."不，不是.它返回一个与其参数相同类型的值.请参阅文档，例如Math.Floor 方法(双).

"Math.Floor is supposed to take a decimal or double and return an integer." No, it isn't. It returns a value of the same type as its argument. See the documentation, e.g. Math.Floor Method (Double).

我本来希望 VS 建议在分配的 RHS 周围添加 CInt() 的修复程序；你没有看到吗?

I would have expected VS to suggest a fix of adding CInt() around the RHS of the assignment; did that not appear for you?

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