C ++嵌套条件运算符循环

问题描述

我很好奇c ++如何处理此嵌套的条件运算符.我半确定自己了解这是如何工作的，但我很好奇，有人可以通过图表解释循环如何执行嵌套的条件运算符.

I'm curious about how c++ handles this nested conditional operator. I'm half sure that I understand how this works, but I'm curious, could anyone explain through a diagram how the loop would execute the nested conditional operator.

例如，循环会针对每个实例执行每个条件运算符的第一个表达式吗?

For example would the loop execute through the first expression of each conditional operator for each instance?

此嵌套条件运算符的结构还如下:

Also is this nested conditional operator structured as:

(i< 2)? x [i]:y；

(i < 2) ? x[i] : y;

！i? y:x [1];

!i ? y : x[1];

我想我对此很好奇.除非您有能力对循环如何执行此条件运算符进行详尽的解释，否则请不要回答.

I guess I'm just very curious about the nature of this. Please don't answer unless you are capable of giving me a thorough adequate explanation of how the loop executes this conditional operator.

#include "stdafx.h"
#include <iostream>

using namespace std;

int _tmain(int argc, _TCHAR* argv[])

{
const char x[2] [20] = {" Cloud "," at your service\n"};
const char * y = "Strife";
for (int i = 0; i < 7; i++)
    cout << (( i < 2)? !i ? x [i] : y : x[1]);

cout << endl << endl << x[0] << endl << x[1] << endl;

cin.get();
cin.get();
return 0;
}

推荐答案

如有疑问，请清楚说明...

When in doubt, spell it out...

for (int i = 0; i < 7; i++)
{
    if (i < 2) {
        if (!i) { // technically, this is "if i == 1"
            cout << x[i];
        } else { // and this is "if i == 0"
            cout <<y;
        }
    } else {
        cout << x[1];
    }
}

只需简单地阅读一下声明. ?之前的所有内容都放入if，然后只需打开{，直到我们看到:.

Simply go through the statement. Everything before a ? goes in an if, then just open a { until we see a :.

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