问题描述
在ARC中，我知道您不会在-dealloc的任何替代中调用[super dealloc]，因此通常我不这样做而删除其中的观察者和计时器.但是，如果我要细分一个使在-dealloc中释放观察信息而不在该方法的子类的实现中调用[super dealloc]的视图的子类，那么将自动调用super实现以释放由超类处理的观察信息，还是会泄漏?
In ARC I'm aware that you do not call [super dealloc] in any overrides of -dealloc, so typically I remove observers and timers in there without doing so. However, if I were to subclass a view that I made that releases observation info in -dealloc without calling [super dealloc] in the subclass' implementation of the method, would the super implementation be called automatically to release the observation info handled by the superclass, or would it leak?
推荐答案
将自动调用dealloc的超类实现(据我所知，编译器会为您插入语句[super dealloc]).
The superclass' implementation of dealloc is automatically called (as far as I know, the compiler inserts the statement [super dealloc] for you).
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