问题描述
我有一个作业队列,我想创建一个包含四个线程的池,我可以在其中投放我的作业.我所困扰的是如何制作线程并在没有工作时保持它们暂停.
I have a queue of jobs and I want to make a pool of four threads where I can throw my jobs at. What I am stuck at is in how to make the threads and keep them suspended while there is no work.
JOB QUEUE | job1 | job2 | job3 | job4 | ..
THREAD POOL | thread1 | thread2 | thread3 | thread4 |
要创建我目前在初始化点拥有的线程:
To create the threads I have currently at the initialisation point:
for (t=0; t<num_of_threads; t++){
pthread_create(&(threads[t]), NULL, doSth2, NULL);
}
其中 num_of_threads=4
和 doSth2
是一个内部没有任何内容的函数.因此,一旦我创建了 4 个线程并使用 doSth2
完成了它们,我该如何在不杀死它们的情况下为它们提供新的工作?
Where num_of_threads=4
and doSth2
is a function with nothing inside.So once I have created the 4 threads and they are done with doSth2
, how can I give them new work to do, without killing them?
推荐答案
线程池的关键是队列.这是我开发的线程池的修改函数.
The key to a thread pool is a queue. Here are modified functions for a thread pool I have developed.
void queue_add(queue q, void *value)
{
pthread_mutex_lock(&q->mtx);
/* Add element normally. */
pthread_mutex_unlock(&q->mtx);
/* Signal waiting threads. */
pthread_cond_signal(&q->cond);
}
从队列中获取元素
void queue_get(queue q, void **val_r)
{
pthread_mutex_lock(&q->mtx);
/* Wait for element to become available. */
while (empty(q))
rc = pthread_cond_wait(&q->cond, &q->mtx);
/* We have an element. Pop it normally and return it in val_r. */
pthread_mutex_unlock(&q->mtx);
}
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