将逗号分隔的数字分成对的 Pythonic 方法

问题描述

我想将逗号分隔的值分成对:

>>>s = '0,1,2,3,4,5,6,7,8,9'>>>对 = # 一些 Pythonic 的东西>>>对[(0, 1), (2, 3), (4, 5), (6, 7), (8, 9)]

#something pythonic 会是什么样子?

您将如何检测和处理具有奇数组数字的字符串?

解决方案

类似:

zip(t[::2], t[1::2])

完整示例:

>>>s = ','.join(str(i) for i in range(10))>>>秒'0,1,2,3,4,5,6,7,8,9'>>>t = [int(i) for i in s.split(',')]>>>吨[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]>>>p = zip(t[::2], t[1::2])>>>磷[(0, 1), (2, 3), (4, 5), (6, 7), (8, 9)]>>>

如果项目数是奇数，最后一个元素将被忽略.只包含完整的对.

I'd like to split a comma separated value into pairs:

>>> s = '0,1,2,3,4,5,6,7,8,9'
>>> pairs = # something pythonic
>>> pairs
[(0, 1), (2, 3), (4, 5), (6, 7), (8, 9)]

What would # something pythonic look like?

How would you detect and handle a string with an odd set of numbers?

解决方案

Something like:

zip(t[::2], t[1::2])

Full example:

>>> s = ','.join(str(i) for i in range(10))
>>> s
'0,1,2,3,4,5,6,7,8,9'
>>> t = [int(i) for i in s.split(',')]
>>> t
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> p = zip(t[::2], t[1::2])
>>> p
[(0, 1), (2, 3), (4, 5), (6, 7), (8, 9)]
>>>

If the number of items is odd, the last element will be ignored. Only complete pairs will be included.

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