问题描述
假设我有一个n by- n矩阵A和一个n by- n矩阵B.我想创建一个由矩阵A的N个块作为对角线以及矩阵B的(N -1)个块作为A对角线以下的对角线组成的块矩阵C.
Suppose I have an n-by-n matrix A and an n-by-n matrix B. I want to create a block matrix C consisting of N blocks of matrix A as a diagonal and (N-1) blocks of matrix B as a subdiagonal below the A diagonal.
此链接为以下问题提供了答案只有街区对角线的情况，都很棒.现在我想添加一个块对角线，我应该在Matlab中使用哪个命令?
This link gives answers for only the block diagonal case, which are all great. Now I want to add a block subdiagonal, which command in Matlab should I use?
非常感谢您的帮助.
推荐答案
如果您知道如何创建对角线A(大小为nN -by- nN)的矩阵C，则可以也可以创建较小尺寸的矩阵D(n(N-1)-n(N-1))，其对角线为B，则只需在C的右子矩阵处添加D:
If you know how to create a matrix C with A on its diagonal (of size nN-by-nN), you can also create a matrix D of smaller size (n(N-1)-by-n(N-1)) with B on its diagonal, then you just need to add D at the right sub-matrix of C:
C( (n+1):end, (n+1):end ) = C( (n+1):end, (n+1):end ) + D;
或者，使用 kron :
Alternatively, using kron:
C = kron( eye(n), A ) + kron( diag(ones(n-1,1), -1), B );
在这里使用稀疏矩阵可能会更好
You might be better off using sparse matrices here
C = kron( speye(n), A ) + kron( spdiag(ones(n-1,1), -1, n, n), B );
这篇关于在Matlab中使用重复块创建块对角线和对角线的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！