如何在UIPanGestureRecognizer方法中获取当前触摸点和上一个触摸点？

问题描述

我是iOS新手，我在我的项目中使用 UIPanGestureRecognizer 。在我拖动视图时，我需要获取当前触摸点和上一个触摸点。我很难得到这两点。

I am new to iOS, I am using UIPanGestureRecognizer in my project. In which I have a requirement to get current touch point and previous touch point when I am dragging the view. I am struggling to get these two points.

如果我使用 touchesBegan 方法而不是使用 UIPanGestureRecognizer ，我可以通过以下代码获得这两点：

If I use touchesBegan method Instead of using UIPanGestureRecognizer, I could get these two points by the following code:

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event{
    CGPoint touchPoint = [[touches anyObject] locationInView:self];
    CGPoint previous=[[touches anyObject]previousLocationInView:self];
}

我需要在 UIPanGestureRecognizer中获得这两点/ code>事件火灾方法。我怎样才能做到这一点？请指导我。

I need to get these two points in UIPanGestureRecognizer event fire method. How can I achieve this? please guide me.

推荐答案

你可以使用这个：

CGPoint currentlocation = [recognizer locationInView:self.view];

通过设置当前位置（如果找不到）并每次添加当前位置来存储先前的位置。

Store previous location by setting current location if not found and adding current location everytime.

previousLocation = [recognizer locationInView:self.view];

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