SomeMethod(()=> x.Something)在C#中是什么意思

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(请注意代码是示例)

我有以下语法:

SomeMethod(() => x.Something)

表达式中的前括号是什么意思?

What do the first brackets mean in the expression?

我也很好奇如何从传入的参数中获取属性名称.这可能吗?

I'm also curious how you can get the property name from argument that is being passed in. Is this posssible?

这是不带参数的方法的lambda语法.如果采用1个参数，则为:

It's the lambda syntax for a method that takes no parameters. If it took 1 parameter, it'd be:

SomeMethod(x => x.Something);

如果使用n + 1个参数，则为:

If it took n + 1 arguments, then it'd be:

SomeMethod((x, y, ...) => x.Something);

如果您的SomeMethod使用Expression<Func<T>>，则可以:

If your SomeMethod takes an Expression<Func<T>>, then yes:

void SomeMethod<T>(Expression<Func<T>> e) {
    MemberExpression op = (MemberExpression)e.Body;
    Console.WriteLine(op.Member.Name);
}

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SomeMethod(()=&gt; x.Something)在C#中是什么意思