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问题描述

使用,我试图返回一个不可修改的地图视图。假设我有以下方法,

  public final Map< Foo,Bar> getMap(){
...
return Collections.unmodifiableMap(map);
}

为什么在别的地方执行以下操作,

  Map< Foo,Bar> map = getMap(); 
map.put(...);

这不会抛出一个。有人可以解释一下,还是建议如何成功地返回真正不可修改的地图?

解决方案

你确定你不是掩饰你的例外吗?这样做很好,因为它会引发 UnsupportedOperationException

  import java .util *。 

public class Test {

public static void main(String [] args){
Map< String,String> map = getMap();
map.put(a,b);
}

public static final Map< String,String> getMap(){
Map< String,String> map = new HashMap< String,String>();
map.put(x,y);
return Collections.unmodifiableMap(map);
}
}

我建议您打印出 map.getClass()对方法的返回值 - 我会期望它是一个 UnmodifiableMap 。 / p>

Using Collections.unmodifiableMap(...), I'm trying to return an unmodifiable view of a map. Let's say I have the following method,

public final Map<Foo, Bar> getMap(){
    ...
    return Collections.unmodifiableMap(map);
}

Why is it legal elsewhere to do the following,

Map<Foo, Bar> map = getMap();
map.put(...);

This doesn't throw an UnsupportedOperationException like I thought it would. Can someone please explain this, or suggest how I can successfully return a truly unmodifiable map?

解决方案

Are you sure you're not masking your exceptions somehow? This works absolutely fine, in that it throws UnsupportedOperationException:

import java.util.*;

public class Test {

    public static void main(String[] args) {
        Map<String, String> map = getMap();
        map.put("a", "b");
    }

    public static final Map<String, String> getMap(){
        Map<String, String> map = new HashMap<String, String>();
        map.put("x", "y");
        return Collections.unmodifiableMap(map);
    }
}

I suggest you print out map.getClass() on the return value of the method - I would expect it to be an UnmodifiableMap.

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06-27 20:44