本文介绍了如何以json格式输出的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
大家好........
hi all........
[WebMethod]
[ScriptMethod(UseHttpGet = true, ResponseFormat = ResponseFormat.Json)]
public string Inserttblval(string UserName, int CountryId, int IsActive)
{
int rowsInserted;
SqlConnection conn = new SqlConnection("Data Source=SREENI\\SQLEXPRESS;Initial Catalog=TestDB;User ID=sa;Password=sa123");
string sql = string.Format(@"INSERT INTO [TestDB].[dbo].[Table_1] ([CountryId],[UserName],[IsActive]) VALUES ({0},'{1}',{2})", CountryId,UserName, IsActive);
SqlCommand cmd = new SqlCommand();
cmd.Connection = conn;
cmd.CommandText = sql;
cmd.CommandType = CommandType.Text;
conn.Open();
rowsInserted = cmd.ExecuteNonQuery();
conn.Close();
cmd = null;
return string.Format("CountryId,UserName, IsActive");
}
错误是
错误3找不到类型或命名空间名称'ScriptMethodAttribute'（您是否缺少using指令或程序集引用？）E：\mine\webserviceasp.net1 \\ \\ App_Code \ WebService.cs 39 5 webserviceasp.net1
error is
Error3The type or namespace name 'ScriptMethodAttribute' could not be found (are you missing a using directive or an assembly reference?)E:\mine\webserviceasp.net1\App_Code\WebService.cs395webserviceasp.net1
推荐答案
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
after
[WebMethod]
ie。
ie.
[WebMethod]
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
public string Inserttblval(string UserName, int CountryId, int IsActive)
{
}
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