本文介绍了如何实现广度优先遍历?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这就是我所拥有的。我认为预订是相同的,并首先将其与深度混合!

This is what I have. I thought pre-order was the same and mixed it up with depth first!

import java.util.LinkedList;
import java.util.Queue;

public class Exercise25_1 {
  public static void main(String[] args) {

    BinaryTree tree = new BinaryTree(new Integer[] {10, 5, 15, 12, 4, 8 });

    System.out.print("\nInorder: ");
    tree.inorder();
    System.out.print("\nPreorder: ");
    tree.preorder();
    System.out.print("\nPostorder: ");
    tree.postorder();

    //call the breadth method to test it

    System.out.print("\nBreadthFirst:");
    tree.breadth();

  }
}

class BinaryTree {
  private TreeNode root;


  /** Create a default binary tree */
  public BinaryTree() {
  }

  /** Create a binary tree from an array of objects */
  public BinaryTree(Object[] objects) {
    for (int i = 0; i < objects.length; i++) {
      insert(objects[i]);
    }
  }

  /** Search element o in this binary tree */
  public boolean search(Object o) {
    return search(o, root);
  }

  public boolean search(Object o, TreeNode root) {
    if (root == null) {
      return false;
    }
    if (root.element.equals(o)) {
      return true;
    }
    else {
      return search(o, root.left) || search(o, root.right);
    }
  }

  /** Return the number of nodes in this binary tree */
  public int size() {
    return size(root);
  }

  public int size(TreeNode root) {
    if (root == null) {
      return 0;
    }
    else {
      return 1 + size(root.left) + size(root.right);
    }
  }

  /** Return the depth of this binary tree. Depth is the
  * number of the nodes in the longest path of the tree */
  public int depth() {
    return depth(root);
  }

  public int depth(TreeNode root) {
    if (root == null) {
      return 0;
    }
    else {
      return 1 + Math.max(depth(root.left), depth(root.right));
    }
  }

  /** Insert element o into the binary tree
  * Return true if the element is inserted successfully */
  public boolean insert(Object o) {
    if (root == null) {
      root = new TreeNode(o); // Create a new root
    }
    else {
      // Locate the parent node
      TreeNode parent = null;
      TreeNode current = root;
      while (current != null) {
        if (((Comparable)o).compareTo(current.element) < 0) {
          parent = current;
          current = current.left;
        }
        else if (((Comparable)o).compareTo(current.element) > 0) {
          parent = current;
          current = current.right;
        }
        else {
          return false; // Duplicate node not inserted
        }
      }

      // Create the new node and attach it to the parent node
      if (((Comparable)o).compareTo(parent.element) < 0) {
        parent.left = new TreeNode(o);
      }
      else {
        parent.right = new TreeNode(o);
      }
    }

    return true; // Element inserted
  }

  public void breadth() {
  breadth(root);
  }

//  Implement this method to produce a breadth first

//  search traversal
  public void breadth(TreeNode root){
      if (root == null)
          return;

      System.out.print(root.element + " ");
      breadth(root.left);
      breadth(root.right);
 }


  /** Inorder traversal */
  public void inorder() {
    inorder(root);
  }

  /** Inorder traversal from a subtree */
  private void inorder(TreeNode root) {
    if (root == null) {
      return;
    }
    inorder(root.left);
    System.out.print(root.element + " ");
    inorder(root.right);
  }

  /** Postorder traversal */
  public void postorder() {
    postorder(root);
  }

  /** Postorder traversal from a subtree */
  private void postorder(TreeNode root) {
    if (root == null) {
      return;
    }
    postorder(root.left);
    postorder(root.right);
    System.out.print(root.element + " ");
  }

  /** Preorder traversal */
  public void preorder() {
    preorder(root);
  }

  /** Preorder traversal from a subtree */
  private void preorder(TreeNode root) {
    if (root == null) {
      return;
    }
    System.out.print(root.element + " ");
    preorder(root.left);
    preorder(root.right);

  }

  /** Inner class tree node */
  private class TreeNode {
    Object element;
    TreeNode left;
    TreeNode right;

    public TreeNode(Object o) {
      element = o;
    }
  }

}


推荐答案

广度优先搜索

Queue<TreeNode> queue = new LinkedList<BinaryTree.TreeNode>() ;
public void breadth(TreeNode root) {
    if (root == null)
        return;
    queue.clear();
    queue.add(root);
    while(!queue.isEmpty()){
        TreeNode node = queue.remove();
        System.out.print(node.element + " ");
        if(node.left != null) queue.add(node.left);
        if(node.right != null) queue.add(node.right);
    }

}

这篇关于如何实现广度优先遍历?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

06-14 10:48