本文介绍了编写一个代码来找出可以绘制多少非重叠的斜率+1线。找出有多少组共线线段。的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有'n'个点 - (x1,y1),(x2,y2),(x3,y3),....,(xn,yn)。任意两个点(xi,yi)和(xj,yj)可以通过一条直线连接。
找出可以绘制多少非重叠的斜率+1线。找出存在多少组共线线段(当存在至少两个线段时称为一组)
There are 'n' points -(x1,y1),(x2,y2),(x3,y3),....,(xn,yn). Any two points(xi,yi) and (xj,yj) can be connected by a straigth line.
Find out how many non-overlapping lines of slope +1 can be drawn. Find out how many sets of collinear lines segments are present.(It is called a set, when at least two lines segments are present)
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