问题描述
我想使用函子将结构 HeapNode
添加到 std :: priority_queue
.
I want to add struct HeapNode
to std::priority_queue
using a functor.
#include <iostream>
#include <queue>
#include <algorithm>
using namespace std;
struct HeapNode
{
bool operator()(const struct HeapNode &a,const struct HeapNode &b) const
{
return b.c>=a.c;
}
double c;
double v;
}h;
int main()
{
priority_queue<struct HeapNode,vector<struct HeapNode>,h> H;
struct HeapNode a={1,2};
struct HeapNode b={3,2};
struct HeapNode c={6,2};
H.push(a);
H.push(b);
H.push(c);
}
但是有错误:
queue.cpp: In function ‘int main()’:
queue.cpp:19:65: error: type/value mismatch at argument 3 in template parameter list for ‘template<class _Tp, class _Sequence, class _Compare> class std::priority_queue’
priority_queue<struct HeapNode,vector<struct HeapNode>,heapnode> H;
^
queue.cpp:19:65: note: expected a type, got ‘heapnode’
queue.cpp:23:4: error: request for member ‘push’ in ‘H’, which is of non-class type ‘int’
H.push(1);
^
queue.cpp:24:4: error: request for member ‘push’ in ‘H’, which is of non-class type ‘int’
H.push(2);
^
queue.cpp:25:4: error: request for member ‘push’ in ‘H’, which is of non-class type ‘int’
H.push(3);
^
我已经研究了参考文献,但对 std :: priority_queue
仍然感到困惑.
I have researched the reference but I'm still confused about std::priority_queue
.
推荐答案
h
指定具有静态存储持续时间的对象.priority_queue模板需要一个类型.错误很明显:
h
designates an object with static storage duration. The priority_queue template expects a type. The error is quite clear on this:
error: type/value mismatch at argument 3 in template parameter list
现在,您将类型本身用作函子来进行比较有点奇怪(且效率低下).我建议将其拆分:
Now, it's a bit strange (and inefficient) that you use the type itself as a functor to compare it. I recommend splitting it:
struct HeapNode
{
double c;
double v;
};
struct HeapNodeCompare
{
bool operator()(const struct HeapNode &a,const struct HeapNode &b) const
{
return b.c>=a.c;
}
};
现在,您的队列可以简单地定义为:
Now your queue can be defined simply as such:
priority_queue<HeapNode, vector<HeapNode>, HeapNodeCompare> H;
(1)我说效率低下,因为必须默认构造函子才能使用.您的类型具有占用存储空间的有意义状态.如果将类型本身用作函子,那会很浪费.单独的类型没有状态,并且将占用最少的存储空间.
(1) I say inefficient because a functor has to be default constructed in order to be used. Your type has meaningful state that occupy storage. If you use the type itself as a functor, that's a bit wasteful. The separate type has no state and will occupy minimal storage.
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