本文介绍了在传输组件的两面都具有树结构的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在使用 antd的Transfer 组件.使用文档中给出的示例,我能够创建一个类似于以下内容的树形转移盒:
I am using antd's Transfer component. Using the examples given in the documentation, I am able to create a tree transfer box that looks similar to:
有没有办法在右侧也有树形结构?当前,当我在0-1
下选择0-1-0
时,它在右侧显示为平坦.
Is there a way I could have a tree structure also on the right side? Currently, as I select 0-1-0
under 0-1
, it appears flat on the right side.
沙盒示例中给出的代码如下:
import React from 'react';
import ReactDOM from 'react-dom';
import 'antd/dist/antd.css';
import './index.css';
import { Transfer, Tree } from 'antd';
const { TreeNode } = Tree;
// Customize Table Transfer
const isChecked = (selectedKeys, eventKey) => {
return selectedKeys.indexOf(eventKey) !== -1;
};
const generateTree = (treeNodes = [], checkedKeys = []) => {
return treeNodes.map(({ children, ...props }) => (
<TreeNode {...props} disabled={checkedKeys.includes(props.key)}>
{generateTree(children, checkedKeys)}
</TreeNode>
));
};
const TreeTransfer = ({ dataSource, targetKeys, ...restProps }) => {
const transferDataSource = [];
function flatten(list = []) {
list.forEach(item => {
transferDataSource.push(item);
flatten(item.children);
});
}
flatten(dataSource);
return (
<Transfer
{...restProps}
targetKeys={targetKeys}
dataSource={transferDataSource}
className="tree-transfer"
render={item => item.title}
showSelectAll={false}
>
{({ direction, onItemSelect, selectedKeys }) => {
if (direction === 'left') {
const checkedKeys = [...selectedKeys, ...targetKeys];
return (
<Tree
blockNode
checkable
checkStrictly
defaultExpandAll
checkedKeys={checkedKeys}
onCheck={(
_,
{
node: {
props: { eventKey },
},
},
) => {
onItemSelect(eventKey, !isChecked(checkedKeys, eventKey));
}}
onSelect={(
_,
{
node: {
props: { eventKey },
},
},
) => {
onItemSelect(eventKey, !isChecked(checkedKeys, eventKey));
}}
>
{generateTree(dataSource, targetKeys)}
</Tree>
);
}
}}
</Transfer>
);
};
const treeData = [
{ key: '0-0', title: '0-0' },
{
key: '0-1',
title: '0-1',
children: [{ key: '0-1-0', title: '0-1-0' }, { key: '0-1-1', title: '0-1-1' }],
},
{ key: '0-2', title: '0-3' },
];
class App extends React.Component {
state = {
targetKeys: [],
};
onChange = targetKeys => {
console.log('Target Keys:', targetKeys);
this.setState({ targetKeys });
};
render() {
const { targetKeys } = this.state;
return (
<div>
<TreeTransfer dataSource={treeData} targetKeys={targetKeys} onChange={this.onChange} />
</div>
);
}
}
ReactDOM.render(<App />, document.getElementById('container'));
我要转移的方式如下图所示.
The way I want to transfer is depicted in the images below.
- 我希望能够转移孩子们
- 转移孩子时,左表应将剩余的孩子置于父项之下,右表应将其转移的孩子置于父项之下.
推荐答案
查看此示例其中:
-
TransferTree
是检查节点并显示树路径的示例. -
AntdTreeTransfer
具有传输时树路径的Transfer
组件的示例.
TransferTree
is an example of checking nodes and showing the tree path.AntdTreeTransfer
an example forTransfer
component with tree path on transfer.
export const renderTreeNodes = data =>
data.map(item =>
item.children ? (
<Tree.TreeNode title={item.title} key={item.key} dataRef={item}>
{renderTreeNodes(item.children)}
</Tree.TreeNode>
) : (
<Tree.TreeNode {...item} dataRef={item} />
)
);
export const filterTree = (keys, halfKeys, rootNode) =>
rootNode
? rootNode
.filter(node => keys.includes(node.key) || halfKeys.includes(node.key))
.map(nodeRoot => ({
...nodeRoot,
children: filterTree(keys, halfKeys, nodeRoot.children)
}))
: [];
export default function TreeTransfer() {
const [checkedNodes, setCheckedNodes] = useState([]);
const onCheck = (selectedKeys, info) => {
const filteredTree = filterTree(selectedKeys, info.halfCheckedKeys, data);
setCheckedNodes(filteredTree);
};
return (
<FlexBox>
<Row type="flex" gutter={20}>
<Col>
<Card>
<Tree checkable defaultExpandAll onCheck={onCheck}>
{renderTreeNodes(data)}
</Tree>
</Card>
</Col>
<Col>
<Card>
<Tree checkable defaultExpandAll>
{renderTreeNodes(checkedNodes)}
</Tree>
</Card>
</Col>
</Row>
</FlexBox>
);
}
export default function AntdTreeTransfer() {
const [leftCheckedKeys, setLeftCheckedKeys] = useState([]);
const [checkedNodes, setCheckedNodes] = useState([]);
const [targetNodes, setTargetNodes] = useState([]);
return (
<FlexBox>
<Transfer
operations={['', 'Clear']}
onChange={(_, direction) => {
setLeftCheckedKeys([]);
direction === 'right'
? setTargetNodes(checkedNodes)
: setTargetNodes([]);
}}
style={{ width: '50vh' }}
>
{({ direction, onItemSelect, selectedKeys }) =>
direction === 'left' ? (
<Tree
showLine
blockNode
checkable
defaultExpandAll
checkedKeys={leftCheckedKeys}
onCheck={(selectedKeys, info) => {
setLeftCheckedKeys(selectedKeys);
const filteredTree = filterTree(
selectedKeys,
info.halfCheckedKeys,
data
);
setCheckedNodes(filteredTree);
const eventKey = info.node.props.eventKey;
onItemSelect(eventKey, selectedKeys.includes(eventKey));
}}
>
{renderTreeNodes(data)}
</Tree>
) : (
<Tree
autoExpandParent
blockNode
checkable
onCheck={(selectedKeys, info) => {
const eventKey = info.node.props.eventKey;
onItemSelect(eventKey, selectedKeys.includes(eventKey));
}}
>
{renderTreeNodes(targetNodes)}
</Tree>
)
}
</Transfer>
</FlexBox>
);
}
这篇关于在传输组件的两面都具有树结构的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!