问题描述
我正在尝试用 python 打开一个串口.这是在 Ubuntu 上.我导入 openinterface.py 并输入这个
I am trying to open a serial port with python. This is on Ubuntu. I import the openinterface.py and enter in this
ser = openinterface.CreateBot(com_port = "/dev/ttyUSB1", mode="full")
我收到一条错误消息，提示- 的操作数类型不受支持:‘str’和‘int’"我尝试使用单引号而不是双引号进行相同的调用，并且根本没有引号.
I get an error saying "unsupported operand types for -: 'str' and 'int'" I tried the same call with single quotes instead of double, and with no quotes at all.
我该如何解决这个问题?或者是否有其他功能可以使用?我只知道 Python 的基础知识，所以也许我没有注意到它的一些小语法?任何帮助将不胜感激，谢谢.
How can I fix this? Or is there an alternative function to use? I only know the basics of Python so maybe its some small syntax thing I am not noticing? Any help would be appreciated, thanks.
推荐答案
根据 俄语页面，openinterface.py 文件存在一个错误，试图从端口参数中减去一个.它建议使用 sed 进行此更改(删除第 803 行的 -1):
According to this page in Russian, there's a bug with the openinterface.py file that tries to subtract one from the port argument. It suggests making this change (removing the - 1 on line 803) with sed:
sed -ie "803s/ - 1//" openinterface.py
要么尝试一下，要么看看是否有 openinterface.py 的更新版本.
Either try that, or see if there's an updated version of openinterface.py.
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