问题描述
在一个文件中查找某些日志时，我得到两种类型的日志(一种带有空格，一种不带空格).我现在想使用一个正则表达式从这些日志中提取 doSomething 和 doAnotherThing .
When looking for some logs in one file I got two types of logs (one with white spaces and one without).I would now like to extract doSomething and doAnotherThing out of these logs with one regular expression.
日志文件1:"taskType":"doSomething"
日志文件2:"taskType":"doAnotherThing"
我编写了这个正则表达式: taskType .....(?< taskType1> \ w +)
I coded this regular expression: taskType.....(?<taskType1>\w+)
它对日志文件1有效，但对日志文件2无效，因为它剪切了单词的前两个字符.有没有解决这个问题的方法?
It works good for Logfile 1 but not for Logfile 2, because it cuts the first two characters of the word. Is there a way to eliminate this issue?
谢谢！
推荐答案
"tasktype" \ s?:\ s?((doSomething | doAnotherThing)" 对我有用，请尝试此处 https://regex101.com/r/Mx1RtT/1
"taskType"\s?:\s?"(doSomething|doAnotherThing)" works for me, try it here https://regex101.com/r/Mx1RtT/1
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