本文介绍了两个字符串之间的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在C#中有一个简单的方法:
I have simple method in C# :
public static string BetweenOf(string ActualStr, string StrFirst, string StrLast)
{
return ActualStr.Substring(ActualStr.IndexOf(StrFirst) + StrFirst.Length, (ActualStr.Substring(ActualStr.IndexOf(StrFirst))).IndexOf(StrLast) + StrLast.Length);
}
我该如何优化呢?
推荐答案
以下是与正则表达式测试相提并论:
Here's how the code from @Chris here stacks up against a regular expression test:
void Main()
{
string input = "abcdefghijklmnopq";
string first = "de";
string last = "op";
Regex re1 = new Regex("de(.*)op", RegexOptions.None);
Regex re2 = new Regex("de(.*)op", RegexOptions.Compiled);
// pass 1 is JIT preheat
for (int pass = 1; pass <= 2; pass++)
{
int iterations = 1000000;
if (pass == 1)
iterations = 1;
Stopwatch sw = Stopwatch.StartNew();
for (int index = 0; index < iterations; index++)
BetweenOfFixed(input, first, last);
sw.Stop();
if (pass == 2)
Debug.WriteLine("IndexOf: " +
sw.ElapsedMilliseconds + "ms");
sw = Stopwatch.StartNew();
for (int index = 0; index < iterations; index++)
BetweenOfRegexAdhoc(input, first, last);
sw.Stop();
if (pass == 2)
Debug.WriteLine("Regex adhoc: " +
sw.ElapsedMilliseconds + "ms");
sw = Stopwatch.StartNew();
for (int index = 0; index < iterations; index++)
BetweenOfRegexCached(input, first, last);
sw.Stop();
if (pass == 2)
Debug.WriteLine("Regex uncompiled: " +
sw.ElapsedMilliseconds + "ms");
sw = Stopwatch.StartNew();
for (int index = 0; index < iterations; index++)
BetweenOfRegexCompiled(input, first, last);
sw.Stop();
if (pass == 2)
Debug.WriteLine("Regex compiled: " +
sw.ElapsedMilliseconds + "ms");
}
}
public static string BetweenOfFixed(string ActualStr, string StrFirst,
string StrLast)
{
int startIndex = ActualStr.IndexOf(StrFirst) + StrFirst.Length;
int endIndex = ActualStr.IndexOf(StrLast, startIndex);
return ActualStr.Substring(startIndex, endIndex - startIndex);
}
public static string BetweenOfRegexAdhoc(string ActualStr, string StrFirst,
string StrLast)
{
// I'm assuming you don't replace the delimiters on every call
Regex re = new Regex("de(.*)op", RegexOptions.None);
return re.Match(ActualStr).Groups[1].Value;
}
private static Regex _BetweenOfRegexCached =
new Regex("de(.*)op", RegexOptions.None);
public static string BetweenOfRegexCached(string ActualStr, string StrFirst,
string StrLast)
{
return _BetweenOfRegexCached.Match(ActualStr).Groups[1].Value;
}
private static Regex _BetweenOfRegexCompiled =
new Regex("de(.*)op", RegexOptions.Compiled);
public static string BetweenOfRegexCompiled(string ActualStr, string StrFirst,
string StrLast)
{
return _BetweenOfRegexCompiled.Match(ActualStr).Groups[1].Value;
}
输出:
IndexOf: 1419ms
Regex adhoc: 7788ms
Regex uncompiled: 1074ms
Regex compiled: 682ms
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