本文介绍了Math.abs为Integer.Min_VALUE返回错误的值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

此代码:

System.out.println(Math.abs(Integer.MIN_VALUE));

返回 -2147483648

它是否应该返回绝对值 2147483648

Should it not return the absolute value as 2147483648 ?

推荐答案

Integer.MIN_VALUE -2147483648 ,但最高值为32位整数可以包含 +2147483647 。试图在32位int中表示 +2147483648 将有效地翻转到 -2147483648 。这是因为,当使用有符号整数时, +2147483648 -2147483648 的二进制补码表示相同。但是,这不是问题,因为 +2147483648 被视为超出范围。

Integer.MIN_VALUE is -2147483648, but the highest value a 32 bit integer can contain is +2147483647. Attempting to represent +2147483648 in a 32 bit int will effectively "roll over" to -2147483648. This is because, when using signed integers, the two's complement binary representations of +2147483648 and -2147483648 are identical. This is not a problem, however, as +2147483648 is considered out of range.

稍微阅读一点在这个问题上,你可能想查看。

For a little more reading on this matter, you might want to check out the Wikipedia article on Two's complement.

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06-13 01:09