从多个文件中删除six.b

问题描述

我在项目中有数十个文件，我想将 six.b("...")的所有出现更改为 b"..." .我可以使用某种正则表达式bash脚本来做到这一点吗?

I have dozens of files in the project and I want to change all occurences of six.b("...") to b"...". Can I do that with some sort of regex bash script?

推荐答案

完全可以在Python中实现，但是我首先要对项目树进行备份，然后:

It's possible entirely in Python, But I would first make a backup of my project tree, and then:

import re
import os

indir = 'files'

for root, dirs, files in os.walk(indir):
    for f in files:
        fname = os.path.join(root, f)
        with open(fname) as f:
            txt = f.read()
        txt = re.sub(r'six\.(b\("[^"]*"\))', r'\1', txt)
        with open(fname, 'w') as f:
            f.write(txt)
        print(fname)

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