一个指定的时间间隔前一个字符字符串分割为一个字符串数组

问题描述

我在找一个字符串分割成String数组在一个区间，但我不想一半被削减的话。例如：

I'm looking to split a string into a String array over an interval, but I don't want the words to be cut in half. For Example:

说出文字是：

Lorem Ipsum Sub Rosa Dolores Clairborne. The quick brown fox zipped quickly to the tall yellow fence and hopped to the other side.
Interval: 50

将被分为以下

separated[0]: "Lorem Ipsum Sub Rosa Dolores Clairborne. The quick brown"
separated[1]: "fox zipped quickly to the tall yellow fence and"
separated[2]: "hopped to the other side."

我一直试图弄清楚这一点，我想出最好的是：

I've been trying to figure this out, the best I've come up with is:

    private static String[] splitMessage(String text, int interval) {
    char[] splitText = text.toCharArray();
    String[] message = new String[(int) Math.ceil(((text.length() / (double)interval)))];
    int indexOfSpace = 0, previousIndex = 0, messageCursor = 0, pos = 0;
    for (int i = 0; i < splitText.length-1; i++) {
        if (splitText[i] == ' ') {
            indexOfSpace = i;
        }
        if (pos == interval) {
            message[messageCursor] = text.substring(previousIndex, indexOfSpace);
            previousIndex = indexOfSpace;
            messageCursor++;
        }
        pos++;
    }
    return message;
}

这最终只能分裂的Lorem到第一个索引。有什么建议？

This ends up only splitting Lorem into the first index. Any suggestions?

推荐答案

我会建议使用 WordUtils的包裹功能来添加换行符在适当的包装点，然后 String.split（\\\\ \\\\ - [R N'）; 来生成的字符串分割成字符串数组。

I would recommend using the WordUtils's Wrap function to add line breaks at the appropriate wrapping points, and then String.split("\\r?\\n"); to split the resulting string into an array of strings.

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