问题描述
我正在尝试在我的 MySQL 数据库中创建多对多关系.我有三张桌子:Films
、Genres
和 Films_Genres
.我正在使用以下代码来设置它们:
I am trying to create a many-to-many relationship in my MySQL database. I have three tables:Films
, Genres
and Films_Genres
. I am using the following code to set them up:
CREATE TABLE Films
(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
Title VARCHAR(255)
),
CREATE TABLE Genres
(
id INT NOT NULL AUTO_INCREMENT,
PRIMARY KEY(id),
Name VARCHAR(255)
),
CREATE TABLE Films_Genres
(
film_id INT NOT NULL,
genre_id INT NOT NULL,
PRIMARY KEY (film_id, genre_id),
FOREIGN KEY (film_id) REFERENCES Films(id) ON UPDATE CASCADE,
FOREIGN KEY (genre_id) REFERENCES Genres(id) ON UPDATE CASCADE
)
但是,当我尝试将一些值插入到表中时:
However, when I try to insert some values into the tables with:
INSERT INTO Films (Title) VALUES ('$title')
INSERT INTO Genres (Name) VALUES ('$genre')
我可以在 Films
表中看到新电影,在 Genres
表中看到新类型,但是Films_Genres
表没有更新 - 没有新行(我正在通过 phpMyAdmin 检查).
I can see the new Film in Films
table and the new Genre in Genres
table butthe Films_Genres
table doesn't update - there are no new rows (I'm checking through phpMyAdmin).
我做错了什么?
推荐答案
你不会在 Films_Genres
表中看到任何东西,除非你明确地在其中插入一些东西.通过 PK 和 FK 实现的参照完整性不适用于为您填充表.
You won't see anything in Films_Genres
table until you explicitly insert something in it.Referential integrity through PK and FK is not for populating your tables for you.
在Films_Genres
中插入新记录的MySql代码,如果是对应新类型的新电影,可能看起来像
Your MySql code for inserting a new record in Films_Genres
, if it's a new film which correspond to a new genre, might look like
INSERT INTO Films (Title) VALUES ('Title1');
SET @film_id = LAST_INSERT_ID();
INSERT INTO Genres (Name) VALUES ('Genre1');
SET @genre_id = LAST_INSERT_ID();
INSERT INTO Films_Genres (film_id, genre_id) VALUES(@film_id, @genre_id);
在 php 方面,要为自动增量字段获取新分配的 id,请使用 $mysqli->insert_id
.
现在,如果您想制作一部新电影并同时将其分配给多种类型,您可以这样做
Now if you want to create a new film and assign it to multiple genres at once you can do
INSERT INTO Films (Title) VALUES ('Title2');
SET @film_id = LAST_INSERT_ID();
-- if you get ids of genre from your UI just use them
INSERT INTO Films_Genres (film_id, genre_id)
SELECT @film_id, id
FROM Genres
WHERE id IN (2, 3, 4);
INSERT INTO Films (Title) VALUES ('Title3');
SET @film_id = LAST_INSERT_ID();
-- if you names of genres you can use them too
INSERT INTO Films_Genres (film_id, genre_id)
SELECT @film_id, id
FROM Genres
WHERE Name IN ('Genre2', 'Genre4');
这里是 SQLFiddle 演示
Here is SQLFiddle demo
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