Scrapy FormRequest 发送 JSON

问题描述

我正在尝试创建一个可以发送 content-type:application/json 的 FormRequest.

I am trying to create a FormRequest that can send content-type:application/json.

这是我的尝试:

yield FormRequest("abc.someurl.com", formdata=json.dumps({"referenceId":123,"referenceType":456}), headers={'content-type':'application/json'}, callback=self.parseResult2)

如果我使用json.dumps()来处理formdata=中的表单数据，我得到的错误是

If I use json.dumps() to process the form data in the formdata=, the error I get is

"exceptions.ValueError: 需要 1 个以上的值来解包"

我不能像

formdata={"referenceId":123,"referenceType":456}

FormRequest 有效但未被服务器接受.

The FormRequest works but is not accepted by the server.

import requests
import json
result = requests.post(url, json.dumps({"referenceId":123,"referenceType":456}), headers={'content-type':'application/json'})

它在 python 命令提示符下工作，如上所示.

It works from the python command prompt as in the above.

有什么想法吗?

-公里

推荐答案

FormRequest 用于模拟 HTML 表单(例如 application/x-www-form-urlencoded).听起来你只是想用你的请求发布数据.由于您提到了application/json"的内容类型，因此您可能想要执行以下操作:

FormRequest is for simulating an HTML form (e.g. application/x-www-form-urlencoded). It sounds like you are simply wanting to POST data with your Request. Since you mention a content type of 'application/json' you probably want to do something like this:

request = Request( url, method='POST',
                   body=json.dumps(my_data),
                   headers={'Content-Type':'application/json'} )

这篇关于Scrapy FormRequest 发送 JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！