问题描述
Java中有没有办法告诉它只返回IPv6?我已经尝试了所有的东西而无法让它发挥作用。
Is there a way in Java to tell it to return IPv6 only? I've tried everything and can't get it to work.
try
{
InetAddress inet = InetAddress.getByName(hostName);
boolean status = inet.isReachable(5000);
if (status)
{
System.out.println(inet.getCanonicalHostName() + " Host Reached\t" + java.net.Inet6Address.getByName(hostName).getHostAddress());
}
else
{
System.out.println(inet.getCanonicalHostName() + " Host Unreachable");
}
}
catch (UnknownHostException e)
{
System.err.println("Host does not exists");
}
catch (IOException e)
{
System.err.println("Error in reaching the Host");
}
我用来尝试仅返回IPv6的行:
The line I use to try to return IPv6 only:
System.out.println(inet.getCanonicalHostName() + " Host Reached\t" + java.net.Inet6Address.getByName(hostName).getHostAddress());
这会不断返回IPv4。任何人都知道为什么这样做?
This keeps returning IPv4. Anyone have any idea of why its doing this?
推荐答案
java.net.Inet6Address
不会覆盖 getByName()
因此它将始终返回特定的IPv4地址
,除非您的参数本身在有效的IPv6地址的形式,在这种情况下,此方法将返回Inet6Address-Object。
java.net.Inet6Address
does not override getByName()
so it will always return the specific IPv4-Address,unless your parameter itself is in the form of an valid IPv6-Address, in this case this method will return an Inet6Address-Object.
例如:
getByName(stackoverflow.com)
- > Inet4Address
getByName(2001:0db8:85a3:08d3:1319:8a2e:0370:7344)
- > Inet6Address
For example:getByName("stackoverflow.com")
--> Inet4AddressgetByName("2001:0db8:85a3:08d3:1319:8a2e:0370:7344")
--> Inet6Address
InetAddress.getByName() - 文档
>对于在文字IPv6地址中指定的主机,要么
RFC 2732中定义的格式或RFC 2373中定义的文字IPv6地址格式为
接受。<
因此,如果您想获取IPv6地址,则需要在参数中定义它,或者配置DNS服务器以返回IPv6地址而不是IPv4地址。
So if you want to get an IPv6-Address you need to define it within your parameter, or configure a DNS-Server to return the IPv6-Address instead of the IPv4-Address.
检索IPv6地址的另一种方法是使用 InetAddress.getAllByName(www.google.at)
返回所有已知的IP-主持人的地址。
Another way to retrieve the IPv6-Address is using InetAddress.getAllByName("www.google.at")
which returns all known IP-Addresses of the host.
例如,您可以使用此方法过滤返回的数组,该数组返回第一个IPv6地址或 null
如果主持人没有:
For example you can use this method to filter the returned array, which return the first IPv6-Address or null
if the host don't have one:
public Inet6Address getIPv6Addresses(InetAddress[] addresses) {
for (InetAddress addr : addresses) {
if (addr instanceof Inet6Address) {
return (Inet6Address) addr;
}
}
return null;
}
更新:
更多功能,尤其是影响DNS服务器的那些,我建议使用外部库DNSJava,因为DNS支持的普通Java实现很差。
当前代码:
public class Ping
{
public void pingHost (String hostName)
{
try
{
InetAddress[] inet = InetAddress.getAllByName(hostName);
String address = this.getIPv4Addresses(inet).getHostAddress();
boolean status = this.getIPv6Addresses(inet).isReachable(5000);
if (status)
{
System.out.println(reverseDns(address) + " Host Reached\t" + this.getIPv6Addresses(inet).getHostAddress());
}
else
{
System.out.println(this.getIPv6Addresses(inet).getCanonicalHostName() + " Host Unreachable");
}
}
catch (UnknownHostException e)
{
System.err.println("Host does not exists");
}
catch (IOException e)
{
System.err.println("Error in reaching the Host");
}
}
public Inet6Address getIPv6Addresses(InetAddress[] addresses)
{
for (InetAddress addr : addresses)
{
if (addr instanceof Inet6Address)
{
return (Inet6Address) addr;
}
}
return null;
}
public Inet4Address getIPv4Addresses(InetAddress[] addresses)
{
for (InetAddress addr : addresses)
{
if (addr instanceof Inet4Address)
{
return (Inet4Address) addr;
}
}
return null;
}
public static String reverseDns(String hostIp) throws IOException
{
Resolver res = new ExtendedResolver();
Name name = ReverseMap.fromAddress(hostIp);
int type = Type.PTR;
int dclass = DClass.IN;
Record rec = Record.newRecord(name, type, dclass);
Message query = Message.newQuery(rec);
Message response = res.send(query);
Record[] answers = response.getSectionArray(Section.ANSWER);
if (answers.length == 0)
return hostIp;
else
return answers[0].rdataToString();
}
}
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