一个Javascript数组中的偶数和？

问题描述

试图将斐波那契数列的偶数相加。为什么不把所有的数字相加在一起，只用最后一个数字？我怎样才能把所有的偶数加起来？
这里是我的代码：

$ p $ function fibonacciSum（）{
var i;
var fib = new Array（）;

fib [0] = 0;
fib [1] = 1; （i = 2; i fib [i] = fib [i-2] + fib [i-1]的
;
var number = parseInt（fib [i]）;
var sum = 0;
if（number％2 == 0）{
var result = sum + = fib [i];
}
}
console.log（result）;



解决方案

外循环。试试这个：

  function fibonacciSum（）{
 var i; 
 var fib = new Array（）; 
 
 fib [0] = 0; 
 fib [1] = 1; 
 var sum = 0; 
 var result = 0; （i = 2; i  fib [i] = fib [i-2] + fib [i-1]的
; 
 var number = fib [i]; 
 if（number％2 == 0）{
 result = sum + = fib [i]; 
} 
} 
 console.log（result）; 
} 
  

Trying to sum the even numbers of the fibonacci sequence. Why is it not summing all of the numbers together and just using the last number? How can I sum all of the even numbers together? Here's my code:

function fibonacciSum(){
    var i;
    var fib = new Array ();

    fib[0] = 0;  
    fib[1] = 1; 
        for(i=2; i<=10; i++){  
            fib[i] = fib[i-2] + fib[i-1]; 
            var number = parseInt(fib[i]);   
            var sum = 0;  
            if (number % 2 == 0) {  
                var result = sum += fib[i];  
                }  
         }  
    console.log(result);   
}

解决方案

You should declare sum and result outside for loop. Try this:

function fibonacciSum(){
    var i;
    var fib = new Array ();

    fib[0] = 0;  
    fib[1] = 1;
    var sum = 0; 
    var result = 0; 
    for(i=2; i<=10; i++){  
        fib[i] = fib[i-2] + fib[i-1]; 
        var number = fib[i]; 
        if (number % 2 == 0) {  
            result = sum += fib[i];  
        }  
     }  
    console.log(result);   
}

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