Django-包含应用网址

问题描述

我具有以下结构（Django 1.4）：

  contains_dir / 
 myproject / 
 myapp1 / 
 myapp2 / 
 myapp3 / 
  

myproject，myapp1，myapp2和myapp3都具有 init .py，所以它们都是模块。

在manage.py中（在containing_dir下）我有 os.environ.setdefault（ DJANGO_SETTINGS_MODULE， myproject.settings）

在我的myproject.settings中定义：

  [..] 
 ROOT_URLCONF ='myproject.urls'
 INSTALLED_APPS =（
 [..] 
'myproject.myapp1'，
'myproject.myapp2'，
'myproject.myapp3'，
）
 [..] 
  

在myapp1.urls.py中，我定义：

  urlpatterns = pattern（'myapp1'，
 url（r'^ agent / $'，'views.agent'，name ='agent'）
）
  

，然后尝试将其导入myproject.urls，然后尝试导入myapp1 ur像这样：

 （r'^ myapp1 /'，include（'myproject.myapp1.urls'））
  

但是每当我尝试加载 localhost：8000 / myapp1 / agent 我得到

 异常值：没有名为myapp1 
   
 
 
我认为从myapp1.urls扔掉
 
 
 
有什么帮助吗？谢谢
解决方案
您必须拥有
  __ init__.py 
  
文件位于 myproject目录中。当您说：
 （r'^ myapp1 /'，include（'myproject.myapp1.urls'））
  
您是说 myproject（以及myapp1）是一个python packege。
 
I have the following structure (Django 1.4):
containing_dir/
    myproject/
        myapp1/
        myapp2/
        myapp3/
myproject, myapp1, myapp2, and myapp3 all have init.py, so they're all modules.
In manage.py (under containing_dir) I have os.environ.setdefault("DJANGO_SETTINGS_MODULE", "myproject.settings")
in myproject.settings i define:
[..]
ROOT_URLCONF = 'myproject.urls'
INSTALLED_APPS = (   
    [..]
    'myproject.myapp1',
    'myproject.myapp2',
    'myproject.myapp3',
)
[..]
In myapp1.urls.py I define:
urlpatterns = patterns('myapp1',
    url(r'^agent/$', 'views.agent',    name='agent')
)
and I try to import it in myproject.urls I try to import myapp1 urls like this:
(r'^myapp1/', include('myproject.myapp1.urls'))
but whenever I try lo load localhost:8000/myapp1/agent I get
Exception Value: No module named myapp1
I think thrown from withing myapp1.urls
Any help? thanks
 解决方案 
You must have a
__init__.py
file inside your "myproject" directory. When you say:
(r'^myapp1/', include('myproject.myapp1.urls'))
you are saying "myproject" (as well as myapp1) is a python packege.
                        
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