本文介绍了获取JSlider的输入和更改的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我需要使用JSlider来实时获取输入,这意味着它将在不按任何按钮的情况下返回输入.我有滑块的这段代码:

I need to use JSlider with getting input live, meaning that it will return an input without pressing any button. I have this piece of code for the slider:

JPanel panel = new JPanel();
            JSlider js = new JSlider(JSlider.VERTICAL, 0, 20, 10);
            js.setMajorTickSpacing(2);
            js.setPaintTicks(true);
            Hashtable labelTable = new Hashtable();
            labelTable.put(new Integer(js.getMinimum()), new JLabel("x0"));
            labelTable.put(new Integer((js.getMinimum() + js.getMaximum()) / 2), new JLabel("x1"));
            labelTable.put(new Integer(js.getMaximum()), new JLabel("x2"));
            js.setLabelTable(labelTable);
            js.setPaintLabels(true);
            panel.add(js);
            int result = JOptionPane.showConfirmDialog(null, panel, "choose size", JOptionPane.YES_OPTION);

是否有可能这样做?我以为可以使用actionListener,但是没有成功.

Is it even possible to do so? I thought using actionListener but I didn't succeed.

推荐答案

例如,可以使用ChangeListener

It's possible, using a ChangeListener, for example

slider.addChangeListener(new ChangeListener() {

    @Override
    public void stateChanged(ChangeEvent e) {
        JSlider slider = (JSlider) e.getSource();
        int value = slider.getValue();
        ...
    }
});

这篇关于获取JSlider的输入和更改的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-09 17:44