问题描述
我想在运行时能够等同于以下内容:
I want to be able to do the equivalent to the following at runtime:
var action = new Action<ANYTHING AT RUNTIME>(obj => Console.WriteLine("Called = " + obj));
我知道我需要为Action获取正确的类型,但不知道如何获得最终的使用Delegate.Create。 在Action定义中表示T。
I know I need to get the correct type for the Action, but not sure how to get the final bit using Delegate.Create. Type
represent T in the Action definition.
var actionType = typeof(Action<>).MakeGenericType(Type);
var constructor = actionType.GetConstructors()[0];
var @delegate = Delegate.CreateDelegate(actionType, <WHAT GOES HERE>);
人们似乎缺少的一点是我正在尝试创建一个Action的实例,其中T可以没有静态指定,因为它是从属性派生的类中使用的 - 这意味着T可以是任何东西,它不能被定义为通用定义
the point people seem to be missing is I'm trying to create an instance of Action where T can not be specified statically because it is being used from a class derived from Attribute - this means T could be anything and it can not be defines as a generic definition
干杯
Cheers
推荐答案
如果你知道你需要执行的操作是什么,如何执行它,不管类型如何,只需做一个通用的方法来执行操作并创建你的代理方式?
If you know what the operation you need to perform is and how to perform it regardless of type (as in your example) why not just make a generic method that performs the operation and create your delegate that way?
class Program
{
public static void Perform<T>(T value)
{
Console.WriteLine("Called = " + value);
}
public static Delegate CreateAction(Type type)
{
var methodInfo = typeof (Program).GetMethod("Perform").MakeGenericMethod(type);
var actionT = typeof (Action<>).MakeGenericType(type);
return Delegate.CreateDelegate(actionT, methodInfo);
}
static void Main(string[] args)
{
CreateAction(typeof (int)).DynamicInvoke(5);
Console.ReadLine();
}
}
这篇关于如何动态创建Action< T>在运行时?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!