Java - Scanner - 跳过我上次的nextLine（）请求

问题描述

所以我早先实例化扫描仪扫描，但它跳过我的第二个 scan.nextLine（）在 scan.nextInt（）之后。我不明白为什么会跳过它？

So I instantiate the Scanner scan a lot earlier but it skips right over my second scan.nextLine() after scan.nextInt(). I don't understand why it skips over it?

     System.out.println("Something: ");

        String name = scan.nextLine();

        System.out.println("Something?: ");

        int number = scan.nextInt();

        System.out.println("Something?: ");

        String insurer = scan.nextLine();

        System.out.println("Something?: ");

        String another = scan.nextLine();

推荐答案

因为当你输入一个数字

    int number = scan.nextInt();

你输入一些数字并点击，它只接受数字并保持缓冲区中的新行字符

you enter some number and hit , it only accepts number and keeps new line character in buffer

所以 nextLine（）只会看到终结符字符，它会认为它是空字符串作为输入，修复它在处理 int

so nextLine() will just see the terminator character and it will assume that it is blank String as input, to fix it add one scan.nextLine() after you process int

例如：

 System.out.println("Something?: ");

 int number = scan.nextInt();

 scan.nextLine(); // <-- 

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