问题描述
我有一个对象数组.在循环过程中，我将不同的属性附加到每个条目.
I have an array of objects. During the loop I append different properties to each entry.
我的问题-如何确保每个条目都具有每个条目的所有属性?
My question - how do I make sure every entry has all the properties of each entry?
让我们考虑一下:
var myArray = [{A: 1}, {B: 2}, {C: 3}];
现在，我想运行一些优雅的单行代码将此数组转换为:
Now I want to run some elegant one-liner to convert this array into:
[{A: 1, B:2, C: 3}, {A: 1, B:2, C: 3}, {A: 1, B:2, C: 3}]
推荐答案
如果没有库，那么优雅的单行代码会有些困难.但是，如果您具有某种extend函数，则可能是:
An elegant one-liner is a bit difficult without a library. But if you have some kind of extend function, then it could be:
myArray.map(function(v) { return extend.apply(null, [{}].concat(myArray)); });
extend函数将需要组合多个对象(作为单独的参数传递). jQuery中可以使用jQuery.extend这样的功能，underscore.js也具有一个功能.
The extend function would require several objects (passed as separate arguments) to be combined. Such a function is available in jQuery as jQuery.extend, and underscore.js also has one.
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