LOAD DATA INFILE 使用 STR_TO_DATE(@var1,'%m/%d/%Y') 转换 2 个日期 - 抛出错误

本文介绍了LOAD DATA INFILE 使用 STR_TO_DATE(@var1,'%m/%d/%Y') 转换 2 个日期 - 抛出错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

这是抛出错误，我无法弄清楚原因，有什么想法吗?

This is throwing an error, I am unable to figure out why, any ideas?

LOAD DATA LOCAL INFILE 'H:/Data/DB__Muni/data/msrb_AZ_short1.csv'
INTO TABLE import_mdrp FIELDS TERMINATED BY ';' LINES TERMINATED BY '\r\n' 
  ( 
    Issuer, cusip6, state, Issue,
    page_pointer, @var1, date_rng, cusip9, @var2,
    yield, Amt_Offer_Dlr, Amt_Offer_Per, Security_Description,
    Fitch, Moody, cusip_img, fitch_img, moody_img 
  )
SET maturity = STR_TO_DATE(@var2,'%m/%d/%Y') 
SET issue_date = STR_TO_DATE(@var1,'%m/%d/%Y') 
;

推荐答案

代替

SET maturity = STR_TO_DATE(@var2,'%m/%d/%Y') 
SET issue_date = STR_TO_DATE(@var1,'%m/%d/%Y')

试试

SET maturity = STR_TO_DATE(@var2,'%Y-%m-%d') 
SET issue_date = STR_TO_DATE(@var1,'%Y-%m-%d')

更新 1

SET maturity = DATE_FORMAT(STR_TO_DATE(@var2, '%m/%d/%Y'), '%Y-%m-%d'),
    issue_date = DATE_FORMAT(STR_TO_DATE(@var1, '%m/%d/%Y'), '%Y-%m-%d')

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