它显示Socket异常未处理，并显示没有这样的主机已知

问题描述

public DestCode（）

{

String strHostName;



string lip =;

strHostName = Dns.GetHostName（）;

IPHostEntry local = Dns.GetHostEntry（strHostName）;

foreach（local.AddressList中的IPAddress ipaddress）

{

lip + = ipaddress.ToString（）;

}

IPAddress [] ipAddress = Dns。 GetHostAddresses（lip）;

IPEndPoint ipEnd = new IPEndPoint（ipAddress [0]，504）;

// ipEnd = new IPEndPoint（IPAddress.Any，504）;

sock = new Socket（AddressFamily.InterNetwork，SocketType.Stream，ProtocolType.IP）;

sock.Bind（ipEnd）;

}

public DestCode()
{
String strHostName;

string lip = "";
strHostName = Dns.GetHostName();
IPHostEntry local = Dns.GetHostEntry(strHostName);
foreach (IPAddress ipaddress in local.AddressList)
{
lip += ipaddress.ToString();
}
IPAddress[] ipAddress = Dns.GetHostAddresses(lip);
IPEndPoint ipEnd = new IPEndPoint(ipAddress[0], 504);
//ipEnd = new IPEndPoint(IPAddress.Any, 504);
sock = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.IP);
sock.Bind(ipEnd);
}

推荐答案

strHostName = Dns.GetHostName();
IPHostEntry local = Dns.GetHostEntry(strHostName);

获取您正在运行的计算机的主机名，然后获取Dns拥有的所有IP地址在名字上。



然后你做了一件令人费解的傻事。你浏览地址列表并将它们连接成一个字符串。

gets the hostname of the machine you're running on, then gets all of the IP addresses Dns has on the name.

Then you do something inexplicably stupid. You go through the address list and concatenate them all together into one string.

foreach (IPAddress ipaddress in local.AddressList)
{
    lip += ipaddress.ToString();
}

??????????????????



所以，我的一台机器的地址列表如下：

????????????????????

So, a list of addresses like this for one of my machines:

fe80::41e0:8932:ac26:3a53%10
fe80::1989:c5e:f944:1ec4%19
fe80::c9bf:c154:b0c5:71d7%20
192.168.1.194
192.168.83.1
192.168.183.1"

在唇变量中变为此。

becomes this in your lip variable.

"fe80::41e0:8932:ac26:3a53%10fe80::1989:c5e:f944:1ec4%19fe80::c9bf:c154:b0c5:71d7%20192.168.1.194192.168.83.1192.168.183.1"

然后你尝试将那堆垃圾解析为主机名。显然，这不起作用，因为该字符串代表垃圾，而不是任何有效的地址。



我不知道你为什么试图解决这些地址。这样做真的没有意义。

and then you try and resolve that pile of garbage to a host name. Obviously, that won't work since that string represents garbage, not a valid address for anything.

I have no idea why you're trying to resolve these addresses. There's really no point in doing that.

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