使用awk(或熟悉的)将多行合并为1行

问题描述

我需要将nmap输出中的多行合并为一行

i need to merge multiple lines from the output of nmap into a single row

从:

Nmap scan report for example.com
22/tcp   open  ssh
80/tcp   open  http
111/tcp  open  rpcbind
1720/tcp open  h323q931
5432/tcp open  postgresql
Nmap scan report for example.com 
22/tcp   open  ssh
80/tcp   open  http
81/tcp   open  hosts2-ns
111/tcp  open  rpcbind
1720/tcp open  h323q931
Nmap scan report for example.com
22/tcp   open  ssh
111/tcp  open  rpcbind
1720/tcp open  h323q931
Nmap scan report for example.com
22/tcp   open     ssh

收件人:

Nmap scan report for example.com
22/tcp   open  ssh 80/tcp   open  http 111/tcp  open  rpcbind 1720/tcp open  h323q931 5432/tcp open  postgresql
Nmap scan report for example.com 
22/tcp   open  ssh 80/tcp   open  http 81/tcp   open  hosts2-ns 111/tcp  open  rpcbind 1720/tcp open  h323q931
Nmap scan report for example.com 
22/tcp   open  ssh 111/tcp  open  rpcbind 1720/tcp open  h323q931
Nmap scan report for example.com 
22/tcp   open     ssh

对于1个主机，应该有2行.第一个从Nmap扫描开始...，另一行是打开的端口信息.我看到许多关于多行与awk合并为1行的问题，但无法解决问题.

For 1 host there should be 2 lines. 1st one is starting with Nmap scan ... and the other row is open port info. I saw many questions about multiple lines into 1 line with awk but could'not come up with something.

推荐答案

为什么不这样做:

awk '$0~"Nmap"{if(output!="")print output;print;output=""}$0!~"Nmap"{output=output""$0" "}END{if(output!="")print output}'

如果$ 0具有"Nmap"，则打印该行.如果没有，请跟踪正在发生的事情，然后在新的Nmap时将其打印出来.

If $0 has "Nmap", print that line. If not, keep track of what is happening, then print it when a new Nmap.

END{}块负责触发未打印的内容.请注意，您正在寻找Nmap来打印出一些东西.另请注意条件$0!~"Nmap"，以避免同样缓冲第一行.

The END{} block takes care of firing what was not printed. Note that you are looking for Nmap to print something out. Also note the condition $0!~"Nmap" to avoid buffering that first line as well.

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