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问题描述

我在Postgresql数据库中存储了一个bytea列。

I have a bytea column stored in Postgresql db.

ColumnName:test

ColumnName:test

Ex:  \x61736461640061736461736400

当我在选择查询中使用encode(test,'escape')时,会得到类似的内容。

When I use encode(test,'escape') in my select query i get something like this.

Ex: asdad\000asdasd\000

但是如果要用Java进行编码转义,该怎么做?
,即如果我有

But How to do it If want to do encode-escape in Java? i.e If i have

String str = \x61736461640061736461736400

如何获取 asdad\000asdasd\000 作为字符串数组?

how to get asdad\000asdasd\000 as array of strings ?

谢谢。

推荐答案

您想要一个字符串数组还是想要 asdad\000asdasd\000 ?您是在使用字节数组还是实际的字符串?

Do you want an array of strings or do you want asdad\000asdasd\000? Are you working with a byte array or an actual String?

字符串到字节数组(如果使用字符串)

String str = "\x61736461640061736461736400"
str = str.substring(2); //get rid of \x
byte [] bytes = new byte[str.length()/2];
for(int i = 0; i < result.length; i++) {
  String numberStr = str.substring(i*2,i*2+2);
  int numberInt = Integer.parseInt(numberStr);
  bytes[i] = (byte) numberInt;
}

字节数组到字符串ArrayList

ArrayList<String> result = new ArrayList<String>();
int startIndex = 0;
for(int i = 0; i < bytes.length; i++) {
  if(bytes[i] == 0) {
    if(startIndex > i) {
      byte [] stringBytes = new byte[i - startIndex];
      for(int j = startIndex; j < i; j++) {
        stringBytes[j-startIndex] = bytes[j];
      }
      result.add(new String(stringBytes, "US-ASCII"));
    }
    startIndex = i+1;
  }
}

字节数组为八进制转义字符串

DecimalFormat formatter = new DecimalFormat("000");
StringBuilder resultBuilder = new StringBuilder();
for(byte b : bytes) {
  if(b > 0) {
    char c = (char) b;
    resultBuilder.append(c);
  } else {
    int bInt = b & 0xFF;
    String octal = Integer.toString(bInt, 8);
    int numPadZeroesNeeded = 3 - octal.length();
    resultBuilder.append('\');
    for(int i = 0; i < numPadZeroesNeeded; i++) {
      resultBuilder.append('0');
    }
    resultBuilder.append(octal);
  }
}

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10-24 14:42