本文介绍了非命名空间范围中的显式专门化的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

template<typename T>
class CConstraint
{
public:
    CConstraint()
    {
    }

    virtual ~CConstraint()
    {
    }

    template <typename TL>
    void Verify(int position, int constraints[])
    {
    }

    template <>
    void Verify<int>(int, int[])
    {
    }
};

在g ++下编译此语句会产生以下错误:

Compiling this under g++ gives the following error:

非命名空间作用域中的显式专门化'class CConstraint'

Explicit specialization in non-namespace scope 'class CConstraint'

在VC中,它编译得很好。任何人都可以让我知道解决方法?

In VC, it compiles fine. Can anyone please let me know the workaround?

推荐答案

VC ++在这种情况下不符合 - 显式专门化必须在命名空间范围。 C ++ 03,§14.7.3/ 2

VC++ is non-compliant in this case - explicit specializations have to be at namespace scope. C++03, §14.7.3/2:

此外,由于C ++ 03,§14.7.3/ 3 ,不能专门化成员函数而不明确专门化包含类,因此一个解决方案是让 Verify / code>转发到一个可能是专门的免费函数:

Additionally you have the problem that you can't specialize member functions without explicitly specializing the containing class due to C++03, §14.7.3/3, so one solution would be to let Verify() forward to a, possibly specialized, free function:

namespace detail {
    template <typename TL> void Verify     (int, int[]) {}
    template <>            void Verify<int>(int, int[]) {}
}

template<typename T> class CConstraint {
    // ...
    template <typename TL> void Verify(int position, int constraints[]) {
        detail::Verify<TL>(position, constraints);
    }
};

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06-09 07:27