问题描述
根据 http://www.workwithcolor.com/color-luminance-2233。 HTM ，红色（＃FF0000）具有亮度：54％。和浅粉色（＃FF8080）具有亮度：89％。我们的设计师喜欢它，但它是如何确定的？试一下： http://www.workwithcolor.com/hsl-color-schemer- 01.htm
According to http://www.workwithcolor.com/color-luminance-2233.htm, RED (#FF0000) has Luminance: 54%. and light pink (#FF8080) has Luminance: 89%. Our designers like it but how is it determined? Try here: http://www.workwithcolor.com/hsl-color-schemer-01.htm
我试图用公布的W3C 相对亮度公式，虽然范围为[ 0,1]，红色是 0.21 和白色是 1.00 。
I tried using relative luminance formula published by W3C and although the range is [0,1], red is 0.21 and white is 1.00.
我在想，也许什么workwithcolor确实是第一次变相的颜色为灰度，并宣读了灰色的亮度。我尝试过，但它仍然无法产生相同的结果。
I'm thinking, maybe what workwithcolor does is first covert the color into grayscale, and read the luminance of the gray. I tried it but it still doesn't give the same result.
我试过到目前为止： http://jsfiddle.net/HytZQ/
推荐答案
在这里查看公式：Formula确定RGB颜色亮度
Check the formula here:Formula to determine brightness of RGB color
Luminance (standard, objective): (0.2126*R) + (0.7152*G) + (0.0722*B)
把R = 255，G = B = 0，你会得到54
Put R=255, and G=B=0, you'll get 54
编辑：对相对亮度，除以最大值（255）你会得到21％
For relative luminance, divide by the maximum (255)you get 21%
有关白，你就会得到100％
For white, you get 100%
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