$ stmt-> bind_param()(如果条件查询)动态

问题描述

当我使用SELECT

这是我的php代码

$sql = 'SELECT ProductName, ProductId  FROM Product WHERE 1=1'
if($produkname != ''){
    $sql .= ' AND ProdukName Like ?';
}
if($produkcode != ''){
    $sql .= ' AND Produkcode Like ?';
}

if($stmt = $mysqli->prepare($sql)){
    $stmt->bind_param ('ss', $produkname, $produkcode)
    $stmt->execute();

    //else code 
}

如果$produkname或$produkcode值之一为空，则我无法bind_param

I cannot bind_param if one of $produkname or $produkcode value is empty

推荐答案

您还可以将call_user_func_array与$stmt->bind_param结合使用来进行类似的操作:

You could also utilize call_user_func_array with $stmt->bind_param to do something like this:

<?php
$sql = 'SELECT ProductName, ProductId  FROM Product WHERE 1=1'

$types = '';
$params = array(&$types);

if($produkname != ''){
    $sql .= ' AND ProdukName Like ?';

    $types .= 's';
    $params[] = $produkname;
}

if($produkcode != ''){
    $sql .= ' AND Produkcode Like ?';

    $types .= 's';
    $params[] = $produkcode;
}

if($stmt = $mysqli->prepare($sql)){
    if (!empty($types)) {
        call_user_func_array(array($stmt, 'bind_param'), $params);
    }

    $stmt->execute();

    //else code 
    }

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