filepath.Join删除点

本文介绍了filepath.Join删除点的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

我对rsync的创建路径有问题.

i have a problem with create path for rsync.

x := filepath.Join("home", "my_name", "need_folder", ".")
fmt.Println(x)

我得到了"home/my_name/need_folder"，但是需要"home/my_name/need_folder/."，如果没有concat怎么解决?在名称为."的linux文件夹中.并非不可能.

I get "home/my_name/need_folder", but need "home/my_name/need_folder/.", how fix without concat? In linux folder with name "." not impossible.

谢谢！

使用 filepath.Join() 作为其文档说明:

You can't do that with the filepath.Join() as its documentation states:

，并且由于.表示当前"值，因此目录，它将被 filepath.Clean() :

And since . denotes the "current" directory, it will be removed by filepath.Clean():

消除每个.路径名元素(当前目录).

Eliminate each . path name element (the current directory).

实际上，您无法使用 path/filepath 包来做您想做的事情完全不支持此操作.

And in fact you can't do what you want with the path/filepath package at all, there is no support for this operation.

您需要手动使用字符串连接.为此使用filepath.Separator会很安全:

You need to use string concatenation manually. Use filepath.Separator for it, it'll be safe:

x := filepath.Join("home", "my_name", "need_folder") +
    string(filepath.Separator) + "."
fmt.Println(x)

输出(在转到游乐场上尝试):

home/my_name/need_folder/.

这篇关于filepath.Join删除点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！