我如何分别从每个父节点获取子节点?

问题描述

我有一些数据 Xml..

I have some Data Xml..

<main>
  <TabNavigator x="27" y="11" width="455" height="376" id="gh" backgroundColor="#A4B6E9">
    <NavigatorContent width="100%" height="100%" label="Client" id="clientTab"></NavigatorContent>
    <NavigatorContent width="100%" height="100%" label="Admin" id="adminTab"></NavigatorContent></TabNavigator>
    <TitleWindow x="521" y="84" width="377" height="234">
      <DataGrid x="0" y="0" width="375" height="163" borderVisible="true" id="details">
        <columns>
          <ArrayList>
            <GridColumn dataField="Name" id="arrayName"/><GridColumn dataField="Address" headerText="Address"/>
            <GridColumn dataField="Phone_Number" headerText="Phone_Number"/>
          </ArrayList>
        </columns>
      </DataGrid>
      <Button x="139" y="167" height="28" label="Export"/>
    </TitleWindow>
</main>

我使用以下代码来检索给定 XML 的子名称..

I use following code for retrieving the child names of given XML..

private function urlLdr_complete(event:Event):void{
var xmlData:XML=new XML(URLLoader(event.currentTarget).data);
for each (var t:XML in xmlData.children())
{
   Alert.show(t.Name);
}

但我只有 2 个孩子(TabNavigator 和 TitleWindow).我如何在每个父节点中获得其他孩子?我希望每个父母都有单独的孩子.我怎样才能得到它?

But I only get 2 children(TabNavigator and TitleWindow).How do I get the other children in each parent node? I want separate children for each parent. How can I get it?

推荐答案

您需要使用递归函数沿着树向下走.使用 trace() 而不是 alert():

You need to use a recursive function to walk down the tree. Using trace() instead of alert():

private function urlLdr_complete(event:Event):void
{
    var xmlData:XML=new XML(URLLoader(event.currentTarget).data);
    showNodeName(xmlData);
}

private function showNodeName($node:XML):void
{
    // Trace the current node
    trace($node.name());
    if($node.hasChildNodes)
    {
        for each (var child:XML in $node.children())
        {
            // Recursively call this function on each child
            showNodeName(child);
        }
    }
}

或者，使用 E4X 后代()函数:

Or, use the E4X descendants() function:

private function urlLdr_complete(event:Event):void
{
    var xmlData:XML=new XML(URLLoader(event.currentTarget).data);
    // Trace the root node:
    trace(xmlData.name());
    // And trace all its descendants:
    for each(var child:XML in xmlData.descendants())
    {
        trace(child.name());
    }
}

两者都应该产生相同的结果:

Both should produce identical outcomes:

main
TabNavigator
NavigatorContent
NavigatorContent
TitleWindow
DataGrid
columns
ArrayList
GridColumn
GridColumn
GridColumn
Button

我还没有测试过，但我希望内置的后代 () 函数更高效.

I haven't tested but I would expect the built-in descendants() function to be more efficient.

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