问题描述
我的程序(碰巧在 Perl 中,尽管我认为这个问题不是特定于 Perl 的)以 Progress: x/yy
形式在程序中的某一点输出状态消息其中 x
和 yy
是一个数字,例如:Progress: 4/38
.
My program (which happens to be in Perl, though I don't think this question is Perl-specific) outputs status messages at one point in the program of the form Progress: x/yy
where x
and yy
are a number, like: Progress: 4/38
.
我想在打印新状态消息时覆盖"之前的输出,这样我就不会用状态消息填充屏幕.到目前为止,我已经尝试过这个:
I'd like to "overwrite" the previous output when a new status message is printed so I don't fill the screen with status messages. So far, I've tried this:
my $progressString = "Progress\t$counter / " . $total . "\n";
print $progressString;
#do lots of processing, update $counter
my $i = 0;
while ($i < length($progressString)) {
print "\b";
++$i;
}
如果我在 $progressString
中包含换行符,则不会打印退格字符.但是,如果我省略换行符,则输出缓冲区永远不会刷新,也不会打印任何内容.
The backspace character won't print if I include a newline in $progressString
. If I leave out the newline, however, the output buffer is never flushed and nothing prints.
对此有什么好的解决方案?
What's a good solution for this?
推荐答案
在 STDOUT 中使用自动刷新:
Use autoflush with STDOUT:
local $| = 1; # Or use IO::Handle; STDOUT->autoflush;
print 'Progress: ';
my $progressString;
while ...
{
# remove prev progress
print "\b" x length($progressString) if defined $progressString;
# do lots of processing, update $counter
$progressString = "$counter / $total"; # No more newline
print $progressString; # Will print, because auto-flush is on
# end of processing
}
print "\n"; # Don't forget the trailing newline
这篇关于更新命令行输出的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!