本文介绍了在Android的动态位图绘制的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想知道我如何从一个动态的变量,它是图像名称/字符串类型设置位图绘制资源:
I am wondering how i can set a Bitmap drawable resource from a dynamic variable that is the image name/ type string:
public CustomIcon getView(int position, View convertView, ViewGroup parent) {
String label;
String image;
DataBaseManager db = new DataBaseManager(context);
label = db.getIconLabel(mIcons.get(position));
image = db.getIconImage(mIcons.get(position));
Bitmap bitmap = BitmapFactory.decodeResource(parent.getResources(),
parent.getResources().getIdentifier(image, "drawable", getApplicationContext().getPackageName()));
Log.v(TAG, "current pos:"+ position);
CustomIcon icon = new CustomIcon(context, bitmap,label);
return icon;
}
有问题的部分是
Bitmap bitmap = BitmapFactory.decodeResource(parent.getResources(),
R.drawable.[image]);
code以上CHANGED -
推荐答案
要解决这个问题的方法是先获取资源ID,然后使用BitmapFactory方式:
The way to deal with this is to get the resource ID first and then use the BitmapFactory method:
String imgName = "myicon";
int resID = parent.getResources().getIdentifier(imgName, "drawable", "my.app.package.name");
Bitmap bitmap = BitmapFactory.decodeResource(parent.getResources(), resID);
这篇关于在Android的动态位图绘制的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!