问题描述
我正在努力使用HttpURLConnection和OutputStreamWriter。
I'm struggling with HttpURLConnection and OutputStreamWriter.
代码实际到达服务器,因为我得到了有效的错误
回复。发出POST请求,但没有收到数据
服务器端。
The code actually reaches the server, as I do get a valid errorresponse back. A POST request is made, but no data is receivedserver-side.
非常感谢任何正确使用此东西的提示。
Any hints to proper usage of this thingy is highly appreciated.
代码在AsyncTask中
The code is in an AsyncTask
protected JSONObject doInBackground(Void... params) {
try {
url = new URL(destination);
client = (HttpURLConnection) url.openConnection();
client.setDoOutput(true);
client.setDoInput(true);
client.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
client.setRequestMethod("POST");
//client.setFixedLengthStreamingMode(request.toString().getBytes("UTF-8").length);
client.connect();
Log.d("doInBackground(Request)", request.toString());
OutputStreamWriter writer = new OutputStreamWriter(client.getOutputStream());
String output = request.toString();
writer.write(output);
writer.flush();
writer.close();
InputStream input = client.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(input));
StringBuilder result = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
Log.d("doInBackground(Resp)", result.toString());
response = new JSONObject(result.toString());
} catch (JSONException e){
this.e = e;
} catch (IOException e) {
this.e = e;
} finally {
client.disconnect();
}
return response;
}
我想发送的JSON:
JSONObject request = {
"action":"login",
"user":"mogens",
"auth":"b96f704fbe702f5b11a31524bfe5f136efea8bf7",
"location":{
"accuracy":25,
"provider":"network",
"longitude":120.254944,
"latitude":14.847808
}
};
我从服务器得到的回复:
And the response I get from the server:
JSONObject response = {
"success":false,
"response":"Unknown or Missing action.",
"request":null
};
我应该得到的回复:
JSONObject response = {
"success":true,
"response":"Welcome Mogens Burapa",
"request":"login"
};
服务器端PHP脚本:
<?php
$json = file_get_contents('php://input');
$request = json_decode($json, true);
error_log("JSON: $json");
error_log('DEBUG request.php: ' . implode(', ',$request));
error_log("============ JSON Array ===============");
foreach ($request as $key => $val) {
error_log("$key => $val");
}
switch($request['action'])
{
case "register":
break;
case "login":
$response = array(
'success' => true,
'message' => 'Welcome ' . $request['user'],
'request' => $request['action']
);
break;
case "location":
break;
case "nearby":
break;
default:
$response = array(
'success' => false,
'response' => 'Unknown or Missing action.',
'request' => $request['action']
);
break;
}
echo json_encode($response);
exit;
?>
Android Studio中的logcat输出:
And the logcat output in Android Studio:
D/doInBackground(Request)﹕ {"action":"login","location":{"accuracy":25,"provider":"network","longitude":120.254944,"latitude":14.847808},"user":"mogens","auth":"b96f704fbe702f5b11a31524bfe5f136efea8bf7"}
D/doInBackground(Resp)﹕ {"success":false,"response":"Unknown or Missing action.","request":null}
如果我追加? action = login
到 URL
我可以从服务器获得成功响应。但只有 action 参数注册服务器端。
If I append ?action=login
to the URL
I can get a success response from the server. But only the action parameter registers server-side.
{success:true,message:欢迎,请求:登录}
结论必须是 URLConnection没有传输数据.write(output.getBytes(UTF-8));
嗯,毕竟数据会被转移。
Well, data get transferred after all.
@greenaps提供的解决方案可以解决问题:
Solution offered by @greenaps does the trick:
$json = file_get_contents('php://input');
$request = json_decode($json, true);
上面的PHP脚本已更新以显示解决方案。
PHP script above updated to show the solution.
推荐答案
echo (file_get_contents('php://input'));
将显示json文本。使用它像:
Will show you the json text. Work with it like:
$jsonString = file_get_contents('php://input');
$jsonObj = json_decode($jsonString, true);
这篇关于HttpURLConnection向Apache / PHP发送JSON POST请求的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!