通过路径获取Alfresco NodeRef（实时，安全的竞争条件）

问题描述

我想获取存储在Alfresco中的文档（或空间）的NodeRef。

I want to get the NodeRef of a document (or space) stored in Alfresco.

我的代码是Java，在Alfresco中运行（例如在AMP中） ）。

My code is in Java, running within Alfresco (for instance in an AMP).

我的代码需要在出现竞争条件时保持安全，例如，它必须找到之前创建的第二个节点。在这种情况下，不能使用（基于搜索）。

My code needs to be safe against race conditions, for instance it must find nodes that have been created a second before. In this context, the usual methods (search-based) can not be used.

怎么办？

推荐答案

您需要避免碰触任何东西SOLR，如

You need to avoid anything that touches SOLR, as those APIs are only Eventually Consistent

具体来说，您需要一个基于。您的用例主要是和。某些

Specifically, you need an API that's based on canned queries. The main ones for your use-case are NodeService.getChildAssocs and NodeService.getChildByName. Some of FileFolderService will work immediately too

您最好的选择是将路径拆分为多个组件，然后通过它进行递归/循环下降。根据要使用名称（ cm：name ）还是QName（基于asoc），您将使用两个 NodeService之一方法

Your best bet would be to split a path into components, then do a recursive / looping descent through it. Depending on if you want it by Name (cm:name) or QName (based on the assoc), you'd use one of the two NodeService methods

例如（未完全测试...）

eg (not fully tested...)

String[] parts = path.split("\\/");
NodeRef nodeRef = nodeService.getRootNode(StoreRef.STORE_REF_WORKSPACE_SPACESSTORE);
for (String name : parts) {
   NodeRef child = nodeService.getChildByName(nodeRef, ContentModel.ASSOC_CONTAINS, name);
   if (child == null) 
      throw new Exception("Path part not found "+name+" in "+path+" at "+nodeRef);
   nodeRef = child;
}
return nodeRef;

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